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allsm [11]
4 years ago
8

Two circular coils are concentric and lie in the same plane. The inner coil contains 110 turns of wire, has a radius of 0.014 m,

and carries a current of 9.0 A. The outer coil contains 160 turns and has a radius of 0.022 m. What must be the magnitude of the current in the outer coil, such that the net magnetic field at the common center of the two coils is zero?
Physics
1 answer:
Hatshy [7]4 years ago
6 0

Answer:

The current flowing through the outer coils is  

Explanation:

From the question we are told that

   The number of turn of inner coil is N _i  =  110 \  turns

    The radius of inner coil is  r_i  =  0.014 \ m

     The current flowing through the inner coil is  I_i  =  9.0 \ A

     The number of turn of outer coil is N_o  =  160 \ turns

     The radius of outer  coil is r_o  =  0.022\ m

For net magnetic field at the common center of the two coils to be  zero  the current flowing in the outer coil must be opposite to current flowing inner coil

   The magnetic field due to inner coils  is mathematically represented as

            B_i  =   \frac{N_i \mu I}{2 r_i}

     The magnetic field due to inner coils  is mathematically represented as

            B_o  =  \frac{N_o \mu I_o}{2 r_o}

Now for magnetic field at center to be zero

             B_o  =  B_i

So

         \frac{N_i \mu I_i}{2 r_i} =  \frac{N_o \mu I_o}{2 r_o}

=>      \frac{110 * 9}{2 *  0.014} =  \frac{160 *I_o}{2 0.022}

         I_o  = 9.72 \ A

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Answer:

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b) The distance of spectator B to the player is 43.9 m

c) The distance between the two spectators is 90.6 m

Explanation:

a) Knowing the time it takes the sound to reach both spectators, we can calculate their position relative to the player, using this equation:

x = v * t

where:

x = position of the spectators

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Then, the position for spectator A relative to the player is:

x = 343 m/s * 0.231 s = 79.2 m

b)For spectator B:

x = 343 m/s * 0.128 s

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The distance of spectator A and B to the player is 79.2 m and 43.9 m respectively.

c) To calculate the distance between the spectators, please see the attached figure. Notice that the distance between the spectators is the hypotenuse of the triangle formed by the sightline of both. We already know the longitude of the two sides. Then, using Pythagoras theorem:

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6 0
4 years ago
For a particular experiment at the SLAC National Accelerator Laboratory, electrons are each accelerated to an energy of exactly
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Answer:

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3 years ago
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Answer:

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The energy of this transition is given by the Planck equation

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Let's apply these equations to our case

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     E = h c / λ

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Now we can use the Bohr equation

Let's reduce to eV

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Let's look for the energy of some levels

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1         -13,606           E₂-E₁ = 10.20

2        -3.4015           E₃-E₂ = 1.89

3        -1.512              E₄- E₃ = 0.662

4        -0.850375

We see the lines of greatest energy for each possible series, the closest to our transition is n₁ = 3 in which a transition from infinity (n = inf) to this level has an energy of 1,512 eV that is very close to the given value

8 0
3 years ago
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Answer:

Explanation:

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Let also assume that;

the heat transfer takes place at a steady-state

1-D flow takes place

No external heat generation; &

No force convection takes place;

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Q = hA(T - T_{\infty})

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Answer:

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