Answer A
x-ray optical telescope.
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Answer:
Mass = 2.8 g
Explanation:
Given data:
Mass of HCl = 102 g
Mass of Zn = 128 g
Mass of H₂ = ?
Solution:
Chemical equation:
2HCl + Zn → H₂ + ZnCl₂
Number of moles of Zn:
Number of moles = mass/molar mass
Number of moles = 128 g/ 65.38 g/mol
Number of moles = 2 mol
Number of moles of HCl:
Number of moles = mass/molar mass
Number of moles = 102 g/ 36.5 g/mol
Number of moles = 2.8 mol
Now we will compare the moles of hydrogen gas with HCl and Zn.
HCl : H₂
2 : 1
2.8 : 1/2×2.8 = 1.4 mol
Zn : H₂
1 : 1
2 : 2
Number of moles of hydrogen formed by HCl are less thus it will limiting reactant.
Mass of Hydrogen:
Mass = number of moles × molar mass
Mass = 1.4 mol × 2 g/mol
Mass = 2.8 g
3.6 x 10²⁴molecules
Explanation:
Given parameters:
Mass of Na = 275g
Unknown:
Number of molecules of Na₂O =
Solution:
Since sodium is the limiting reactant, we first use it to find the number of mole of the Na₂O and transpose it into finding the number of molecules.
Given equation:
4Na + O₂ → 2Na₂O
Since the equation is balanced, let us find the number of moles of Na;
Number of moles =
=
= 11.96moles
From the equation of the reaction;
4 mole of Na produced 2 moles of Na₂O
11.96 moles of Na will produce
= 6moles
1 mole of a substance = 6.02 x 10²³ molecules
6 moles of Na₂O = 6 x 6.02 x 10²³ molecules = 3.6 x 10²⁴molecules
learn more:
Number of moles brainly.com/question/1841136
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Answer:
The structure of the major organic product isolated from the reaction of 1-hexyne with hydrogen chloride (2 mol) is attached below.
Explanation:
Hydracids are added to triple bonds by a mechanism similar to that of the addition to double bonds. The regioselectivity of the addition of H-X to the triple bond follows the rule of Markovnikov, where the Z conformation predominates in the addition of halide to the alkyne, because in the formation of the carbocation it prefers to place the positive charge on the more substituted carbon where the nucleophilic attack of the halide ion will occur.
With respect to the halogenation of the alkene, the same procedure occurs at the time of the formation of the carbocation, joining the nucleophilic ion to the most substituted carbon.