Question

What is the percent-by-mass concentration of acetic acid (CH3COOH) in a vinegar solution that contains 51.80 g acetic acid in a 1.000−L solution? The density of this solution is 1.005 g/mL.

Answer 1

Answer : The percent-by-mass concentration of acetic acid is, 5.15 %

Explanation : Given,

Mass of acetic acid = 51.80 g

Density of solution = 1.005 g/ml

Volume of solution = 1.000 L = 1000 ml      (1 L = 1000 ml)

First we have to calculate the mass of solution.

$\text{Mass of solution}=\text{Density of solution}\times \text{Volume of solution}$

$\text{Mass of solution}=1.005g/ml\times 1000ml=1005g$

Now we have to calculate the percent-by-mass concentration of acetic acid.

$\% \text{ by mass of acetic acid}=\frac{\text{Mass of acetic acid}}{\text{Mass of solution}}\times 100$

Now put all the given values in this formula, we get:

$\% \text{ by mass of acetic acid}=\frac{51.80g}{1005g}\times 100=5.15\%$

Therefore, the percent-by-mass concentration of acetic acid is, 5.15 %