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scoray [572]
3 years ago
6

Suppose you have a gas under 2 atm of pressure and taking up 0.5m ^ 3 of volume. If you compress the gas so that it takes up 0.1

m ^ 3 of volume, what is the new pressure of the gas? О O O 1 atm 10 atm 0.10 atm
Physics
1 answer:
vova2212 [387]3 years ago
5 0

Answer:

10 atm

Explanation:

Assuming the gas is kept at constant temperature, we can apply the following law (Boyle's law):

"For a gas kept at a constant temperature, the pressure of the gas is inversely proportional to its volume"

Mathematically,

pV=const.

where p is the pressure of the gas and V its volume.

The equation can also be rewritten as

p_1 V_1 = p_2 V_2

Where for the gas in the problem, we have:

p_1 = 2 atm is the initial pressure

V_1 = 0.5 m^3 is the initial volume

p_2 is the final pressure

V_2 = 0.1 m^3 is the final volume

Solving for p2,

p_2 = \frac{p_1 V_1}{V_2}=\frac{(2)(0.5)}{0.1}=10 atm

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