Answer:
323.22 ml
Explanation:
Given that :
Diameter, d = 6.8cm
Height, h = 8.9cm
V = arh
Recall :
Volume, V = πr²h
Radius, r = diameter / 2 = 6.8 / 2 = 3.4cm
V = π * 3.4^2 * 8.9
V = 323.21961 cm³
Recall:
1ml = 1cm³
Hence,
323.21961 cm³ = 323.21961 ml
Volume = 323.22 ml
Answer:
Mass of CO₂ produced = 5.72 g
Explanation:
Given data:
Mass of methane = 2.34 g
Mass of oxygen = 8.32 g
Mass of CO₂ produced = ?
Solution:
Chemical equation:
CH₄ + 2O₂ → CO₂ + 2H₂O
Number of moles of methane:
Number of moles = mass/molar mass
Number of moles = 2.34 g/ 16 g/mol
Number of moles = 0.146 mol
Number of moles of oxygen:
Number of moles = mass/molar mass
Number of moles = 8.32 g/ 32 g/mol
Number of moles = 0.26 mol
Now we will compare the moles of carbon dioxide with oxygen and methane.
CH₄ : CO₂
1 : 1
0.146 : 0.146
O₂ : CO₂
2 : 1
0.26 : 1/2×0.26 = 0.13 mol
Less number of moles of CO₂ are produced by oxygen thus oxygen will react as limiting reactant.
Mass of CO₂:
Mass = number of moles × molar mass
Mass = 0.13 mol × 44 g/mol
Mass = 5.72 g
1. 1mL
2. 2mL
3. 0.2mL
4. 0.5mL
