Answer:
The pressure at this depth is 
.
Explanation:
According to the statement, the uncompressed fluid stands at atmospheric pressure. By Boyle's Law we have the following expression:
(1)
Where:
- Initial and final volume.
- Initial and final pressure.
If we know that 
, then the pressure ratio is:
If 
, then the final pressure of the gas is:
The pressure at this depth is .
The east bound train travels at a speed of 95 mile per hour and the west bound train at 75 miles per hour.
Assuming eastbound train will cover distance x then the west bound train will cover distance 272-x .
Therefore, since time taken will be the same then; x/95 = (272-x)/75
= 75x = 95 (272-x)
= 75x = 25840 - 95x
= 170 x= 25840
x = 152 miles
Thus time taken will either be x/95 or (272-x)/75
= 152/95
= 1.6 hours or 1 hour 36 minutes
<h2>Answer:</h2>
<u>The correct option is</u><u> (C) its greater tensile strength </u>
<h2>Explanation:</h2>
Elasticity is the property of any material to return to its original shape when it is de-shaped. for example a spring comes to its original shape when it is stretched and then released. so the property that brings the spring back to its original form is called elasticity. On the other hand tensile strength is the maximum stress that a material can withstands before it breaks. Since polymers are also elastic so the greater tensile strength means greater elasticity.
Answer:
n₂ = 1.15
Explanation:
Given,
Angle of incidence,θ₁ = 50°
refractive index of the glass,n₁ = 1.50
refractive index of liquid = ?
For largest refractive index angle of refraction should be equal to 90°.
Using Snell's law
n₁ sin θ₁ = n₂ sin θ₂
1.50 x sin 50° = n₂ sin 90°
n₂ = 1.15
Hence, refractive index of the liquid is equal to 1.15.
Answer:
v = 2917.35 m/s
Explanation:
let Fc be the centripetal force avting on the satelite , Fg is the gravitational force between mars and the satelite, m is the mass of the satelite and M is the mass of mars.
at any point in the orbit the forces acting on the satelite are balanced such that:
Fc = Fg
mv^2/r = GmM/r^2
v^2 = GM/r
v = \sqrt{GM/r}
= \sqrt{(6.6708×10^-11)(6.38×10^23)/(3.38×10^6 + 1.62×10^6)}
= 2917.35 m/s
Therefore, the orbital velocity of the satelite orbiting mars is 2917.35 m/s.
