1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ede4ka [16]
3 years ago
14

While pushing a refrigerator up a ramp, there would be less friction to overcome if you used a dolly because of the wheels. So t

he efficiency of the ramp would be ________________________ with the use of the dolly.
Physics
1 answer:
FromTheMoon [43]3 years ago
4 0

While pushing a refrigerator up a ramp, there would be less friction to overcome if you used a dolly because of the wheels. So the efficiency of the ramp would be greater with the use of the dolly.

<u>Explanation:</u>

The ramp provides for a wedge setup, so when the refrigerator is being pushed up the ramp, the friction on the ramp would equally distributed to the refrigerator when pushed wholly as the friction applied is a product of the coefficient of friction with the Normal reaction of the weight in contact with the surface.

Therefore, when the dolly is used, the surface in contact becomes divided and thus, the friction applied would become less due to though coefficient of friction remains the same, the normal reaction of the weight becomes small and so does the applied friction. Therefore, efficiency of the ramp increases as the friction is less and work done is more.

You might be interested in
Jenny and Alyssa are members of the cross-country team. On a training run, Jenny starts off and runs at a constant 3.8 m/s. Alys
guapka [62]

Answer:

285 seconds

Explanation:

Jenny speed is 3.8 m/s

Alyssa speed in 4.0 m/s

Alyssa starts after 15 seconds

Find the distance covered by Jenny, when Alyssa starts

Distance=Speed*time

Distance covered by Jenny in 15 seconds= 3.8×15=57m

Relative speed of the two members heading same direction will be;

4.0m/s-3.8m/s=0.2m/s

To find the time Alyssa catch up with Jenny you divide the distance to be covered by Alyssa by the relative speed of the two

Distance=57m, relative speed=0.2m/s  t=57/0.2 =285 seconds

=4.75 minutes

5 0
3 years ago
Read 2 more answers
Can anybody answer this question. Please...
Nady [450]
Yes they acquire both poles. Each side facing each other should be opposites
So A is N
C is S
D is N
B is S
8 0
3 years ago
Why are temperatures in the thermosphere not strictly comparable to those experienced near earth's surface?
Nostrana [21]

Temperatures in the thermosphere are not strictly comparable to those experienced near Earth's surface because the gases of the thermosphere are moving at very high speeds, and the temperature is very high.

The thermosphere lies among the exosphere and the mesosphere. “Thermo” way warmness and the temperature in this layer can reach as much as 4,500 tiers Fahrenheit. in case you have been to hang around inside the thermosphere, though, you'll be very cold because there are not sufficient fuel molecules to transfer the warmth to you.

The thermosphere is the outer layer of the Earth's surroundings, extending from about 53 miles to greater than 370 miles above the surface. The temperature increases rapidly in this layer due to the absorption of huge quantities of incoming excessive electricity sun radiation by using atoms of nitrogen and oxygen.

Learn more about thermosphere here: brainly.com/question/8741747

#SPJ4

4 0
2 years ago
Anyone want to get a conversation going again? lol
marshall27 [118]

Hello

i  am Marie

I lovee cat

7 0
3 years ago
Read 2 more answers
(a) Neil A. Armstrong was the first person to walk on the moon. The distance between the earth and the moon is 3.85 x 108 m. Fin
gizmo_the_mogwai [7]

Answer:

a). 1.28333 seconds

b). 186.66 seconds

Explanation:

a). Given :

Distance between the earth and the moon, d = $3.85 \times 10^8$ m

Speed of the radio waves, c = $3 \times 10^8$ m/s

Therefore the time required for the voice of Neil Armstrong to reach the earth via radio waves is given by :

$t=\frac{d}{c}$

 $=\frac{3.85 \times 10^8}{3 \times 10^8}$

 = 1.28333 seconds

b). Distance between Mars and the earth, d = $5.6 \times 10^{10}$ m

   Speed of the radio waves, c = $3 \times 10^8$ m/s

So, the time required for his voice to reach earth is :

$t=\frac{d}{c}$

 $=\frac{5.6 \times 10^{10}}{3 \times 10^8}$

 = 186.66 seconds

6 0
3 years ago
Other questions:
  • In a Brinell hardness test, a 1500-kg load is pressed into a specimen using a 10-mm-diameter hardened steel ball. The resulting
    14·1 answer
  • A ball falls for 9.0 s increasing its kinetic energy by 2700. If the force acting on the ball in 6.0 N find the following quanti
    12·1 answer
  • PLEASE HELP *WILL AWARD BRAINLIEST*
    11·2 answers
  • Which would be most useful for overcoming the disadvantage of using ores? using public transportation recycling aluminum product
    9·2 answers
  • Planets, stars, asteroids and other celestial bodies have generally round shapes. Some are ovals, others really bumpy circles, a
    15·1 answer
  • a skater increases her speed uniformly from 2.0 m/s to 10 m/s in 3.0s. what is the acceleratioon of the biker?
    10·1 answer
  • The kettle is filled with 5.0 kg of water at 20 °C. The specific heat capacity of water = 4 200 J/Kg °C. Calculate the energy ne
    6·1 answer
  • Which kind of energy does a bullet fired from the gun poseess? How is this energy stored?​
    9·1 answer
  • URGENT HELP IT IS DUE BY TONIGHT PLEASE HELP
    12·1 answer
  • A 120 V fish-tank heater is rated at 130W. Calculate (a) the current through the heater when it is operating, and (b) its resist
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!