Answer:
LOL
Explanation:
IMAGINE POSTING UR CLASSWORK LOLL
Answer:
the spring compressed is 0.1878 m
Explanation:
Given data
mass = 3 kg
spring constant k = 750 N/m
vertical distance h = 0.45
to find out
How far is the spring compressed
solution
we will apply here law of mass of conservation
i.e
gravitational potential energy loss = gain of eastic potential energy of spring
so we say m×g×h = 1/2× k × e²
so e² = 2×m×g×h / k
so
we put all value here
e² = 2×m×g×h / k
e² = 2×3×9.81×0.45 / 750
e² = 0.0353
e = 0.1878 m
so the spring compressed is 0.1878 m
Well,
arctan is a bijection from R into (-pi/2 , pi/2)*and
pi is a period of tangent function:
so
as we have : tan(7pi/4) = tan(pi - pi/4) = - tan(pi/4)
we finally get :
<span>arctan(tan(7pi/4)) = artan(tan(- pi/4)) = - pi/4
</span>
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Answer:
Pressure will triple (Boyle's Law)
Explanation:
Assuming a constant temperature: (compressing gases usually raises the temp significantly):
P1V1 = P2V2
P1V1 / V2 = P2
Now change V2 to 1/3 V2:
P1V1 / (1/3 V2 ) = P2 / (1/3 )
P1V1/ (1/3 v2 ) = 3 P2 <======= THE PRESSURE WILL TRIPLE
This is Boyle's Law
"1 Ampere" (A) means "1 coulomb of charge per second"
140 A means 140 coulombs per second
(140 coulomb/sec) x (0.9 sec) = 126 coulombs of charge.
Go a little farther:
Electrons are the things that move through wire carrying charge.
6.25 x 10¹⁸ electrons carry 1 coulomb of charge.
126 coulombs = 787,500,000,000,000,000,000 electrons (rounded)
