How much work would have to be done to bring a 1150kg automobile traveling at 86km/h to a stop?
1 answer:
Explanation:
We have,
Mass of an automobile is 1150 kg
The automobile traveling at 86 km/h and then it comes to stop.
86 km/h = 23.88 m/s
It is required to find work done by the automobile.
Concept used : Work energy theorem
Th change in kinetic energy of an object is equal to the work done by it. The work done is then given by :
Here, v = 0
or
Therefore, the work done by the automobile is .
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Here we have perfectly inelastic collision. Perfectly inelastic collision is type of collision during which two objects collide, stay connected and momentum is conserved. Formula used for conservation of momentum is:
In case of perfectly inelastic collision v'1 and v'2 are same.
We are given information:
m₁=0.5kg
m₂=0.8kg
v₁=3m/s
v₂=2m/s
v'₁=v'₂=x
0.5*3 + 0.8*2 = 0.5*x + 0.8*x
1.5 + 1.6 = 1.3x
3.1 = 1.3x
x = 2.4 m/s
In case of perfectly inelastic collision v'1 and v'2 are same.
We are given information:
m₁=0.5kg
m₂=0.8kg
v₁=3m/s
v₂=2m/s
v'₁=v'₂=x
0.5*3 + 0.8*2 = 0.5*x + 0.8*x
1.5 + 1.6 = 1.3x
3.1 = 1.3x
x = 2.4 m/s
Answer:
The minimum inductance needed is 2.78 H
Explanation:
Given;
frequency of the AC, f = 26.5 Hz
the root mean square voltage in the circuit, = 41.2 V
the maximum current in the circuit, I₀ = 126 mA
The root mean square current is given by;
The inductive reactance is given by;
The minimum inductance needed is given by;
Therefore, the minimum inductance needed is 2.78 H
Answer:
Inverted
Real
Explanation:
u = Object distance = 30 cm
v = Image distance
f = Focal length = 10 cm
Lens Equation
As, the image distance is positive the image is real and forms on the other side of the lens
As, the magnification is negative the image is inverted
