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3 years ago

11

What minimum radius of curvature may be designed for safe operation of vehicles at 70 mi/hr if the maximum rate of superelevatio

n (e) is 6% and the maximum coefficient of side friction (f) is 0.10?

1 answer:

aleksandr82 [10.1K]3 years ago

5 0

Tell me why i got this question got it right and now won’t remember but i’ll get back at you when i remember

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(1) Calculate fundamental, Second, third and fifth order harmonics of is (t). istl Rower) vit) { Electronic | Equipment (2) If V

LekaFEV [45]

Complete Question

The complete question is shown on the first uploaded image

Answer:

1) The fundamental order harmonics of $i_{s}(t) = \frac{20}{\pi}Sin(wt)$

The second order harmonics is = 0

The third order harmonics is = 0

The fifth order harmonics is = 0

2) The power factor is 0.5

The total harmonic distortion is 1.21

The average power is 424.2 watt

Explanation:

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3 years ago

How does the Ivanpah Solar Plant make electricity?

barxatty [35]

The Ivanpah plant makes electricity mostly by having 352,000 mirrors focus heat from the sun onto three boilers mounted on towers.

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3 years ago

A wastewater plant discharges a treated effluent (w) with a flow rate of 1.1 m^3/s, 50 mg/L BOD5 and 2 mg/L DO into a river (s)

4vir4ik [10]

A wastewater plant discharges a treated effluent (w) with a flow rate of 1.1 m^3/s, 50 mg/L BOD5 and 2 mg/L DO into a river (s) with a flow rate of 8.7 m^3/s, 6 mg/L BOD5 and 8.3 mg/L DO. Both streams are at 20Â°C. After mixing, the river is 3 meters deep and flowing at a velocity of 0.50 m/s. DOsat for this river is 9.0 mg/L. The deoxygenation constant is kd= 0.20 d^-1 and The reaction rate constant k at 20 Â°C is 0.27 d^-1.

The answer therefore would be the number 0.27 divided by two and then square while getting the square you would make it a binomial.

I wont give the answer but the steps

Your Welcome

8 0

4 years ago

A steam turbine has isentropic efficiency of 0.8. Isentropically, it is supposed to deliver work of 100 kW. What is the actual w

trapecia [35]

Answer:

80 kW; 11 kW; 8 kW; 0.6

Explanation:

Part 1

Isentropic turbine efficiency:

$\eta_t = \frac{\text{Real turbine work}}{\text{isentropic turbine work}} = \frac{W_{real}}{W_s}$

$W_{real} = \eta_t*W_s$

$W_{real} = 0.8*100 kW$

$W_{real} = 80 kW$

Part 2

Coefficient of performance COP is defined by:

$COP = \frac{Q_{out}}{W}$

$Q_{out} = W*COP$

$Q_{out} = 5 kW*2.2$

$Q_{out} = 11 kW$

Part 3

(a)

Energy balance for a refrigeration cycle gives:

$Q_{in} + W = Q_{out}$

$3 kW + 5 kW = Q_{out}$

$8 kW = Q_{out}$

(b)

$COP = \frac{Q_{in}}{W}$

$COP = \frac{3 kW}{5 kW}$

$COP = 0.6$

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3 years ago

A transistor can not be used as a

valentinak56 [21]

Variable resistor is the best abs

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4 years ago