Answer:
0.26 mol
Explanation:
using general gas equation
PV=nRT
V=4.1litre= 4.1 dm³
P= 1.78 atm
R= 0.0821
PUT VALUES
I’m pretty sure it is A at least that’s what we did at our school to test this
Answer:
The carbocation intermediate reacts with a nucleophile to form the addition product.
Explanation:
The reaction of benzene with an electrophile is an electrophillic substitution reaction. Here the electrophile replaces hydrogen. There is no formation of carbocation as intermediate in the reaction. Infact there is transition state where the electorphile attacks on benzene ring and at the same time the hydrogen gets removed from the benzene. So a transition carbocation is formed.
The general mechanism is shown in the figure.
i) Attack of the electrophile on the benzene (which is the nucleophile)
ii) The carbocation intermediate loses a proton from the carbon bonded to the electrophile.
iii) the carbocation formation is the rate determining step.
iv) There is no formation of addition product.
Thus the wrong statement is
The carbocation intermediate reacts with a nucleophile to form the addition product.
Answer:
90.37 g
Explanation:
From Avogadro Number,
1 mole of every substance contains a particle number of 6.02×10²³
From the question,
1 mole of CH₄ contains 6.02×10²³ molecules.
But,
1 mole of CH₄ has a mass of 16 g
Therefore,
16 g of CH₄ contains 6.02×10²³ molecules
Then,
Y g will contain 3.4×10²⁴ molecules
Solve for Y
Y = (16× 3.4×10²⁴)/(6.02×10²³)
Y = 90.37 g