Explanation:
Given data
Inductance L=12*10^-³H
Capacitance C= 3.5*10^-6F
Resistance R= 3.3 Ohms
Voltage V=115v
Capacitive reactance Xc=?
inductive reactance Xl=?
Impedance Z=?
Phase angle =?
A. Resonance frequency
In RLC circuit resonance occurs when capacitive reactance equals inductive reactance
f=1/2pi √ LC
f=1/2*3.142 √ 12*10^-³*3.5*10^-6
f=1/6.284*0.0002
f=1/0.00125
f=800HZ
B. Find Irms at resonance.
Irms=R/V
Irms=3.3/115
Irms=0.028amp
Find the capacitive reactance XC in Ohms
Xc=1/2pi*f*C
Xc=1/2*3.142*800*3.5*10^-6
Xc=1/0.0176
Xc=56.8 ohms
To find the inductive reactance
Xl=2pifL
Xl=2*3.142*800*12*10^-3
Xl=60.3ohms
d) Find the impedance Z.
Z=√R²+(Xl-Xc)²
Z=√3.3²+(60.3-56.8)²
Z=√10.89+12.25
Z=√23.14
Z=4.8ohms
Phase angle =
Tan phi=Xc/R=56.8/3.3
Tan phi=17.2
Phi=tan-1 17.2
Phi= 1.51°
Answer:
(a) The initial speed required is 13116 m/s
(b) The escape speed is 10394 m/s
This problem involves the application of newtons laws of gravitation. The forces in action here are conservative and as a result mechanical energy is conserved.
The full calculation can be found in the attachment below.
Explanation:
In both parts (a) and (b) the energy conservation equation were used. Assumption was made that when the object is very far from the planet the distance from the planet's center approaches infinity and the gravitational potential energy approaches zero.
The calculation can be found below.
Answer:
Option D - 0.2 s
Explanation:
We are given;
Initial velocity; u = 7 m/s
Height of table; h = 1.8m
Now,since we want to find the time the car spent in the air, we will simply use one of Newton's equation of motion.
Thus;
h = ut + ½gt²
Plugging in the relevant values, we have;
1.8 = 7t + ½(9.8)t²
4.9t² + 7t - 1.8 = 0
Using quadratic formula to find the roots of the equation gives us;
t = -1.65 or 0.22
We can't have negative t value, thus we will pick the positive one.
So, t = 0.22 s
This is approximately 0.2 s
Answer:
Explanation:
When the two dissimilar bodies rubbed together, they the both of the bodies becomes charged. One of the body gets positive charge and the other body gets negative charge.
the positively charged body loses some electrons and the negatively charged body gains some electrons.
According to the properties of charge when the plastic rod is rubbed with the fur, the plastic rod has a tendency to get the negative charge and the fur has a tendency to get positive charge.
So,
When we rub a plastic rod with a piece of fur, electrons--------------transfer from fur----------------to the -------plastic-----. In the result charging fur with -positive-----------charge and plastic rod with-----negative--------charge.
Answer:
D. The momentum of Car B is three times as great in magnitude as that of car A.
Explanation:
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