Answer:
The conditions for hurricanes differ from the conditions of tornadoes because of D, Tornadoes form over land, while hurricanes form over bodies of water.
Explanation:
Hurricanes form over warm water in tropical ocean settings and tornadoes form over land within storms.
Answer:
Explanation:
Adding any solute to water will increase the boiling temperature, as it reduces the vapour pressure, meaning a slightly higher temperature is required in order for the vapour pressure to become equal to atmospheric pressure and boil the water. Essentially, adding any non-volatile solute (such as salt, baking soda or sugar) to a liquid causes a decrease in the liquid's vapour pressure.
Given:
12.0 M HCl
2.0 liters of a 3.0 M HCl
Required:
volume of concentrated hydrochloric acid
Solution:
M1V1 = M2V2
(12.0 M HCl)V1 = (3.0 M HCl)( 2.0 liters)
V1 = (3.0 M HCl)( 2.0 liters)/ (12.0
M HCl)
V1 = 0.5 liters
Answer:
Mass percent N₂ = 89%
Mass percent H₂ = 11%
Explanation:
First we <u>use PV=nRT to calculate n</u>, which is the total number of moles of nitrogen and hydrogen:
- 1.03 atm * 7.45 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 305 K
So now we know that
- MolH₂ + MolN₂ = 0.307 mol
and
- MolH₂ * 2 g/mol + MolN₂ * 28 g/mol = 3.49 g
So we have a <u>system of two equations and two unknowns</u>. We use algebra to solve it:
Express MolH₂ in terms of MolN₂:
- MolH₂ + MolN₂ = 0.307 mol
Replace that value in the second equation:
- MolH₂ * 2 g/mol + MolN₂ * 28 g/mol = 3.49
- (0.307-MolN₂) * 2 + MolN₂ * 28 = 3.49
- 0.614 - 2MolN₂ + 28molN₂ = 3.49
Now we calculate MolH₂:
- MolH₂ + MolN₂ = 0.307 mol
Finally, we convert each of those mol numbers to mass, to <u>calculate the mass percent</u>:
- N₂ ⇒ 0.111 mol * 28 g/mol = 3.108 g N₂
- H₂ ⇒ 0.196 mol * 2 g/mol = 0.392 g H₂
Mass % N₂ = 3.108/3.49 * 100% = 89.05% ≅ 89%
Mass % H₂ = 0.392/3.49 * 100% = 11.15% ≅ 11%
Well it breaks down into small parts
