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earnstyle [38]
3 years ago
5

Describe how the velocity and acceleration of a skydiver changes as she falls from the plane back to the ground

Physics
2 answers:
Andrews [41]3 years ago
8 0
The velocity and acceleration of the skydiver will increase as she falls to the ground. According to Newton’s Law of gravity.
lidiya [134]3 years ago
8 0

Answer:

Explanation:

The velocity and acceleration of a skydiver increases as she falls from the plane back to the ground. When she will come more closer to earth the force of gravity will increase on her and her velocity will increase so the acceleration. According to the newtons law of gravitation gravity will increase as the distance between the two body decreases.

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The bending of waves such as sound waves, light waves, and waves in water, around obstacles or the edges of openings is called.
kolezko [41]

Answer:

Diffraction

Explanation:

Diffraction is the bending of waves around obstacles and openings. The amount of diffraction increases with increasing wavelength.

4 0
1 year ago
Which statement best explains the movement of electric current from the clouds to the ground during a lightning storm? .
olga2289 [7]
"The <span>ground is positively charged and the clouds are negatively charged " is the statement among the statements given in the question that </span><span>best explains the movement of electric current from the clouds to the ground during a lightning storm. The correct option among all the options that are given in the question is the third option or option "C". </span>
3 0
3 years ago
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3. Do Newton's Laws of Motion apply to a Water Spout? If so, how?
PSYCHO15rus [73]
Yes it’s spills out becasue bucket
6 0
3 years ago
A block with mass m1 = 4.50 kg and a ball with mass m2 = 7.70 kg are connected by a light string that passes over a frictionless
Allisa [31]
1.6a =  \frac{g(m_2 + m_3 - \mu km_1)}{m_1 + m_2 + m_3}  \\  \\ 1.6a(m_1 + m_2 + m_3) = g(m_2 + m_3 - \mu km_1) \\  \\ (1.6a + \mu kg)m_1 + (1.6a - g)m_2 = (g - 1.6a)m_3 \\  \\ m_3 =  \frac{1.6a +\mu kg}{g - 1.6a} m_1 - m_2 \\  \\ m_3 = 22.57 kg
4 0
3 years ago
Consider an old-fashion bicycle with a small wheel of radius 0.17 m and a large wheel of radius 0.92 m. Suppose the rider starts
Gala2k [10]

Answer:

10259.6 m

Explanation:

We are given that

Radius of small wheel,r=0.17 m

Radius of large wheel,r'=0.92 m

Initial velocity,u=0

Time,t=2.7 minutes=162 s

1 min=60 s

Velocity,v=10m/s

Time,t'=13.7 minutes=822 s

Time,t''=4.1 minutes=246 s

v=u+at

Substitute the values

10=0+162a=162a

a=\frac{10}{162}=0.0617m/s^2

s=ut+\frac{1}{2}at^2

Substitute the values

s=\frac{1}{2}(0.0617)(162)^2=809.6 m

s'=vt'=10\times 822=8220 m

a'=\frac{v}{t''}=\frac{10}{246}

s''=\frac{1}{2}a't''^2=\frac{1}{2}\times \frac{10}{246}(246)^2=1230 m

Total distance traveled by rider=s+s'+s''=809.6+8220+1230=10259.6 m

6 0
3 years ago
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