1) 260 km/h
Let's use the following convention:
positive x-direction = east
positive y-direction = north
Here we have to find the north component of the velocity's airplane, which means we have to find its y-component.
We can use the formula:
where
v = 750 km/h is the magnitude of the plane's velocity
is the angle between the direction of the plane and the positive x-axis
Substituting,
2) north of east
In order to find the direction of flight, we have to consider that the vector representing the displacement of the plane is the hypothenuse of a right triangle, of which the displacements along the east and north direction are the sides.
Therefore, we have
is the displacement towards east
is the displacement towards north
Therefore, the angle that gives the direction is given by
And substituting,
and this angle is measured north of east.
An object with volume greater than it mass. to account less density and thus it will float
Answer:
Therefore the velocity of the proton is m/s towards east.
Explanation:
The mass of proton is m= kg.
q= C is the magnitude of the charge of a proton.
The earth's magnetic field is B= T toward north.
Let v be the velocity of the proton towards east.
The angle between the velocity of proton towards east and magnetic field towards north is .
We know that,
Now putting the all values
m/s
Therefore the velocity of the proton is m/s towards east.
Answer:
P= 168258.30696 Pa
Explanation:
Given that
Mass of water vapor m = 19.00 g
Volume of water vapor V = 2.00 L
Temperature of water vapor is T = 111°C
= 384K
Molar mass of water is M = 18.0148 g/mol
Number of moles are
n = m/M
= (1.90 g)/(18.0148 g/mol)
= 0.1054 mol
Pressure inside the container is
P= nRT/V
P= 168258.30696 Pa