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zheka24 [161]
3 years ago
10

Energy from the Sun arrives at the top of the Earth's atmosphere with an intensity of 1.36 kW/m 2 . How long does it take for 3.

55 × 10 9 J to arrive on an area of 4.25 m 2 ?
Physics
1 answer:
alina1380 [7]3 years ago
4 0

Answer:

The time taken by 3.55\times 10^9\ J to arrive on an area of 4.25\ m^2 is 6.14\times 10^5\ seconds.

Explanation:

Given the intensity of the energy is 1.36\ kW/m^2

And the arriving energy is 3.55\times 10^9\ J

Also, the area in which energy is being arriving is 4.25\ m^2

Now, we will use relation between energy (E), intensity of energy (p), area (A) and time (T).

Where energy is in Joule, intensity is in kW/m^2, area is in m^2 and time is in seconds.

The equation is

E=pAT\\\\T=\frac{E}{pA}\\\\T=\frac{3.55\times 10^9}{1.36\times 10^3\times 4.25}\\\\T=0.614\times 10^6\ s\\T=6.14\times 10^5\ seconds

So, the time taken by 3.55\times 10^9\ J to arrive on an area of 4.25\ m^2 is 6.14\times 10^5\ seconds.

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