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Ludmilka [50]
3 years ago
6

A chemist adds 220.0ml of a 0.194 m potassium permanganate kmno4 solution to a reaction flask. calculate the mass in grams of po

tassium permanganate the chemist has added to the flask
Chemistry
1 answer:
Tema [17]3 years ago
5 0

The formula of determining the molarity is:

molarity = \frac{moles of solute}{volume of solution in liters}   -(1)

Volume of solution = 220.0 mL  (given)

Since, 1 mL = 0.001 L

Therefore, volume of the solution = 0.22 L

Molarity = 0.194 M  (given)

Substituting the values in formula (1)

0.194 = \frac{moles of solute}{0.22}

moles of solute= 0.22 L\times 0.194 mole/L = 0.0427 mole

Now, number of moles = \frac{mass}{Molar mass}  -(2)

Molar mass of KMnO_4 = 39.0983+54.938+4\times 15.99 = 158.0323 g/mol

Substituting the value of number of moles and molar mass of KMnO_4 in equation   -(2)

0.0427 mole = \frac{mass}{158.0323 g/mole}

mass = 158.0323 g/mole\times 0.0427 mole = 6.748 g

Hence, the mass in grams of potassium permanganate the chemist has added to the flask is 6.748 g.



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