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ollegr [7]
3 years ago
7

Tech A says that a cylinder leakage test is performed on a cylinder with low compression to determine the severity of the leak a

nd where it is located. Tech B says that most manufacturers consider up to 50% cylinder leakage acceptable. Who is correct?
Engineering
1 answer:
Karolina [17]3 years ago
4 0
Tech A djjdjdndnndndbdbx
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The equation for the velocity V in a pipe with diameter d and length L, under laminar condition is given by the equation V=Δpdsq
Citrus2011 [14]

Answer:

Given that

V=\dfrac{\Delta Pd^2}{32\mu L}

LHS of above given equation have dimension [M^oL^{1}T^{-1}].

Now find the dimension of RHS

Dimension of P = [ML^{-1}T^{-2}].

Dimension of d=  [M^{0}L^{1}T^{0}].

Dimension of μ =  [ML^{-1}T^{-1}].

Dimension of L=  [M^{0}L^{1}T^{0}].

So

\dfrac{\Delta Pd^2}{32\mu L}=\dfrac{[ML^{-1}T^{-2}].[M^{0}L^{1}T^{0}]^2}{[ML^{-1}T^{-1}].[M^{0}L^{1}T^{0}]}

\dfrac{\Delta Pd^2}{32\mu L}=[M^0L^{1}T^{-1}]

It means that both sides have same dimensions.

5 0
3 years ago
A 4 cm diameter sphere of copper is initially at a temperature of 95 °C. It is placed in a very large water bath at time t- 0. T
avanturin [10]

Answer:112.376 s

Explanation:

Given

T_i=95^{\circ}C

T_f=35^{\circ}C

T_\infty \left ( ambient\right )=25^{\circ}C

h=400 watts/\left ( m^{2}^{\circ}C\right )

c=0.385 J/\left ( m^2^{\circ}C\right )

\rho =9 gm/cm^{3}

Using Newton's law of cooling

\frac{T_i-T_{\infty}}{T-T_{\infty}}=e^{\frac{ht}{\rho L_{c}c}}

\frac{95-25}{35-25}=e^{\frac{400\times 3\times 10^{-4}\times t}{9\times 2\times 0.385}}

7=e^{1.7316\times 10^{-2}\times t}

Taking log both side

t=112.376sec

4 0
3 years ago
You have a 12 volt power source running through a circuit that has 3kΩ of resistance, how many amps (in mA) can flow through the
siniylev [52]

Answer:

4mA

Explanation:

For this problem, we will simply apply Ohm's law:

V = IR

V/R = I

I = V / R

I = 12 volt / 3kΩ

I = 4mA

Hence, the current in the circuit is 4mA.

Cheers.

5 0
3 years ago
__ signals always take priority over signs and traffic signals
Mars2501 [29]

Answer:

Stop singnals

Explanation:

4 0
4 years ago
The Environmental Protection Agency (EPA) has standards and regulations that says that the lead level in soil cannot exceed the
DENIUS [597]

Answer:

See below

Explanation:

<u>Check One-Sample T-Interval Conditions</u>

Random Sample? √

Sample Size ≥30? √

Independent? √

Population Standard Deviation Unknown? √

<u>One-Sample T-Interval Information</u>

  • Formula --> CI=\bar{x}\pm t^*(\frac{S_x}{\sqrt{n}})
  • Sample Mean --> \bar{x}=390.25
  • Critical Value --> t^*=2.0096 (given df=n-1=50-1=49 degrees of freedom at a 95% confidence level)
  • Sample Size --> n=50
  • Sample Standard Deviation --> S_x=30.5

<u>Problem 1</u>

The critical t-value, as mentioned previously, would be t^*=2.0096, making the 95% confidence interval equal to CI=\bar{x}\pm t^*(\frac{S_x}{\sqrt{n}})=390.25\pm2.0096(\frac{30.5}{\sqrt{50}})\approx\{381.5819,398.9181\}

This interval suggests that we are 95% confident that the true mean levels of lead in soil are between 381.5819 and 398.9181 parts per million (ppm), which satisfies the EPA's regulated maximum of 400 ppm.

3 0
2 years ago
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