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3 years ago

A 250mL sample of oxygen is collected over water at 30 C and 850 torr pressure. What is the pressure of the dry gas alone?

Chemistry

1 answer:

3241004551 [841]3 years ago

6 0

Answer:

$p_O=818.2torr$

Explanation:

Hello there!

In this case, according to the given equation, it is possible to calculate the mass of oxygen by using the Dalton's law, considering that the total pressure is 850 torr and the vapor pressure of water at 30°C is 31.8 torr:

$P_T=p_O+p_{H_2O}$

Thus, we solve for the pressure of oxygen as follows:

$p_O=P_T-p_{H_2O}\\\\p_O=850torr-31.8torr\\\\p_O=818.2torr$

Best regards!

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4 years ago

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A car is traveling at a speed of 95 mi/h. If there are 0.62137 miles (mi) in a kilometer,

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Answer:

42 m/s

Explanation:

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What mass of NaNO3 must be dissolved to make 838mL of a 1.25 M solution

denis-greek [22]

Answer:

89.04 g of NaNO₃.

Explanation:

We'll begin by converting 838 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

838 mL = 838 mL × 1 L / 1000 mL

838 mL = 0.838 L

Next, we shall determine the number of mole of NaNO₃ in the solution. This can be obtained as follow:

Volume = 0.838 L

Molarity = 1.25 M

Mole of NaNO₃ =?

Mole = Molarity × volume

Mole of NaNO₃ = 1.25 × 0.838

Mole of NaNO₃ = 1.0475 mole

Finally, we shall determine the mass of NaNO₃ needed to prepare the solution. This can be obtained as follow:

Mole of NaNO₃ = 1.0475 mole

Molar mass of NaNO₃ = 23 + 14 + (16×3)

= 23 + 14 + 48

= 85 g/mol

Mass of NaNO₃ =?

Mass = mole × molar mass

Mass of NaNO₃ = 1.0475 × 85

Mass of NaNO₃ = 89.04 g

Therefore, 89.04 g of NaNO₃ is needed to prepare the solution.

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