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tester [92]
3 years ago
13

3. If you wanted the athletic shoe to slide faster on a surface, what might you do to the shoe? Provide at least two ways to mak

e the shoe slide faster, and explain in terms of the force of friction and the coefficient of friction.
Physics
1 answer:
lesya692 [45]3 years ago
6 0
In order to make the athletic shoe to slide faster of a given surface you had to reduce the friction coefficient of the shoe with the surface.

One way to do that is to put some grease of the sole of the shoe, which undoubtedly would reduce the friction coefficient drastically and the shoe would slide more easily.

Also, if you make the sole smoother the shoe the friction coefficient would decrease and, again, the show would slide mor easily.
You might be interested in
1. Which of the following equations can be used to directly calculate an object s momentum, p?
Taya2010 [7]

Answer:

p = mv

Explanation:

The momentum of an object is given by the equation:

p=mv

where

m is the mass of the object

v is the velocity

Since velocity is a vector, it follows that momentum is a vector as well, therefore it has a magnitude and a direction (the same as the velocity).

The SI unit of the momentum is kg \cdot m\cdot  s^{-1}

An important law related to the momentum is the law of conservation of momentum, which states that for an isolated system (= zero net external force on it), the total momentum of the system is conserved.

3 0
3 years ago
A rock is suspended by a light string. When the rock is in air, the tension in the string is 51.9 N . When the rock is totally i
Luden [163]

Answer:

\rho _{liquid}=1995.07kg/m^{3}

Explanation:

When the rock is immersed in unknown liquid the forces that act on it are shown as under

1) Tension T by the string

2) Weight W of the rock

3) Force of buoyancy due to displaced liquid B

For equilibrium we have T_{3}+B = W_{rock}

T_{3}+\rho _{Liquid}V_{rock}g=W_{rock}.....(\alpha)

When the rock is suspended in air for equilibrium we have

T_{1}=W_{rock}....(\beta)

When the rock is suspended in water for equilibrium we have

T_{2} + \rho _{water}V_{rock}g=W_{rock}.....(\gamma)

Using the given values of tension and solving α,β,γ simultaneously for \rho _{Liquid} we get

W_{rock}=51.9N\\31.6+1000\times V_{rock}\times g=51.9N\\\\11.4+\rho _{liquid}V_{rock}g=51.9N\\\\

Solving for density of liquid we get

\rho _{liquid}=\frac{51.9-11.4}{51.9-31.6}\times 1000

\rho _{liquid}=1995.07kg/m^{3}

5 0
3 years ago
How much potential energy does a 20-kg barrel have when it is in the truck whose floor is 5.0 m above the ground? P.E. = J
MrRa [10]
The answer is 980 J.
6 0
3 years ago
Read 2 more answers
QUESTION 3 ( MARKS]
horrorfan [7]

Answer:

392 N

Explanation:

Draw a free body diagram of the rod.  There are four forces acting on the rod:

At the wall, you have horizontal and vertical reaction forces, Rx and Ry.

At the other end of the rod (point X), you have the weight of the sign pointing down, mg.

Also at point X, you have the tension in the wire, T, pulling at an angle θ from the -x axis.

Sum of the moments at the wall:

∑τ = Iα

(T sin θ) L − (mg) L = 0

T sin θ − mg = 0

T = mg / sin θ

Given m = 20 kg and θ = 30.0°:

T = (20 kg) (9.8 m/s²) / (sin 30.0°)

T = 392 N

7 0
4 years ago
The towel has better blank
koban [17]

Answer:

D

Explanation:

Towels Absorb

5 0
3 years ago
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