The equivalent resistance of the two cylindrical conductors connected in parallel is 466 ohm.
<h3>
Resistance</h3>
Resistance is a measure of the opposition to flow of electric current. It is measured in ohms.
It is given by the formula:

Given that R₂ = 469 ohm, hence:

But l₁ = 6l₂, r₁ = (1/5)r₂, hence:
![R_1=\rho \frac{l_1}{A_1}=\rho *\frac{6l_2}{[\pi (1/5)r_2]^2} =150 * \rho \frac{l_2}{[\pi r_2]^2}=30*469=70350\ ohm](https://tex.z-dn.net/?f=R_1%3D%5Crho%20%5Cfrac%7Bl_1%7D%7BA_1%7D%3D%5Crho%20%2A%5Cfrac%7B6l_2%7D%7B%5B%5Cpi%20%281%2F5%29r_2%5D%5E2%7D%20%3D150%20%2A%20%5Crho%20%5Cfrac%7Bl_2%7D%7B%5B%5Cpi%20r_2%5D%5E2%7D%3D30%2A469%3D70350%5C%20ohm)
The equivalent resistance (R) is:

The equivalent resistance of the two cylindrical conductors connected in parallel is 466 ohm.
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Answer:
The work done on the suitcase is, W = 600 J
Explanation:
Given,
The average force exerted by Jose on his suitcase, F = 60 N
Jose carried the suitcase to a distance, S = 10 m
The work done on the suitcase is given by the relation
<em>W = F x S</em>
Substituting the given values in the above equation,
W = 60 N x 10 m
= 600 J
Hence, the work done on the suitcase is, W = 600 J