The correct answers about rusting, air pollution and products of water with rock are:
Option A. oxidation
Option D. Pollutants mix with air and water to make acid rain.
Option B. clay minerals and calcium carbonate
<h3>What is rusting?</h3>
Rusting is the process by which a metal especially reacts with oxygen in the atmosphere and water vapor to form a hydrated oxide of the metal known as hydrated iron (iii) oxide. This is known as rust.
The process is an oxidation process; option A.
<h3>How does air pollution impact chemical weathering?</h3>
Air pollution is the presence of substances in air known as pollutants which makes the air impure.
Air pollution impact chemical weathering as the pollutants mix with air and water to make acid rain which weathers rocks; option D.
<h3>What products are produced when water reacts with sodium in rocks?</h3>
The reaction of water with sodium in rocks result in the formation of clay minerals and calcium carbonate also as limestone, marble or chalk; option B.
In conclusion, the presence of pollutants in air results in acid rain and hence rock weathering.
Learn more rock weathering at: brainly.com/question/2341950
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A)
NH⁴⁺(aq) + H₂O(l) ⇌ NH₃(aq) + H₃0⁺<span>(aq)
- acid </span>a species that able to donate (H+): NH⁴⁺
- base a species that is able to accept a proton (H+): H₂O
- conjugate base a species formed when acid donates a proton (H+): NH₃
- conjugate acid a species formed by a base accepts a proton (H+): H₃0⁺
b)
CN⁻(aq) + H₂O(l) ⇌ HCN(aq) + OH⁻(aq)
- base a species that is able to accept a proton (H+): CN⁻
- acid a species that able to donate (H+): H₂O
- conjugate acid a species formed by a base accepts a proton (H+): HCN
- conjugate base a species formed when acid donates a proton (H+): OH⁻
The value of Triangle G is A) Less than 0.
<h3>
Answer:</h3>
10.6 mol NO
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN - Balanced] 4NH₃ + 5O₂ → 4NO + 6H₂O
[Given] 13.2 mol O₂
<u>Step 2: Identify Conversions</u>
[RxN] 5 mol O₂ → 4 mol NO
<u>Step 3: Stoich</u>
- [DA] Set up:
- [DA] Multiply/Divide [Cancel out units]:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
10.56 mol NO ≈ 10.6 mol NO
Three equivalents of hydrogen
One equivalent of phosphorus
