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svetoff [14.1K]
2 years ago
6

The Pacific plate collides with and is subducted under four other crustal plates. The area where this happens has lots of volcan

ic activity. This area is called the _____.
Physics
2 answers:
snow_lady [41]2 years ago
8 0
The Pacific Ring of Fire.
Sveta_85 [38]2 years ago
5 0
The Pacific plate collides with and is subducted under four other crustal plates. The area where this happens has lots of volcanic activity. This area is called the Ring of Fire. This is a place under the Pacific Ocean and it has numerous volcanic eruptions and earthquakes and so this region is called the Ring of Fire. In this place there are about 450 active and dormant volcanoes and it is almost 75 percent of the volcanoes present in our earth.



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Gravity can be defined as a force of attraction between objects. The effects of gravity can be witnessed in many systems. Which
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C, planets orbit around the sun because of gravity
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2 years ago
6. A 50 N block is raised 2 m. If the net work done on the block is 50 J, what is the applied force on the block?
geniusboy [140]

Answer:

F = 75[J]

Explanation:

We know that work is defined as the product of force by distance.

In this way we have two forces, the weight of the block down, and the force that bring about the block to rise.

W = -(F_{weight*d})+(F_{upward}*d)

where:

W = work = 50 [J]

d = distance = 2 [m]

Fweight = 50 [N]

Fupward [N]

Now replacing:

50=-(50*2)+(F_{upward}*2)\\50+100=F_{upward}*2\\F_{upward}=150/2\\F_{upward}=75[J]

5 0
2 years ago
A 7.00-cm-long wire is pulled along a U-shaped conducting rail in a perpendicular magnetic field. The total resistance of the wi
Anvisha [2.4K]

Answer:

(a) 1.075 N

(b) 4.254 T

Explanation:

(a)

From the question,

Power = Force×Velocity.

P = Fv................... Equation 1

Where P = Power dissipated in the circuit, F = Pulling force of the wire, v = speed of the wire.

make F the subject of the equation

F = P/v................. Equation 2

Given: P = 4.30 W, v = 4.0 m/s.

Substitute into equation 2

F = 4.30/4

F = 1.075 N.

(b)

Applying,

F = BILsinФ.............. Equation 2

Where B = Strength of the magnetic field, I = current in the wire, L = Length of the wire, Ф = angle between the wire and the magnetic field.

make B the subject of the equation

B = F/ILsinФ................... Equation 3

But,

P = I²R...................... Equation 4

Where R = resistance of the wire.

make I the subject of the equation

I = √(P/R)............... Equation 5

Given: P = 4.30 W, R = 0.330 Ω

Substitute into equation 5

I = √(4.3/0.33)

I = √13.03

I = 3.61 A.

Also given: L = 7 cm = 0.07 m, Ф = 90°

Substitute into equation 3

B = 1.075/(0.07×3.61×sin90)

B = 1.075/0.2527

B = 4.254 T.

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