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Monica [59]
3 years ago
14

What happens to the temperture of the water as it changes to steam

Chemistry
1 answer:
mestny [16]3 years ago
3 0
It rises. it can steam before an after boiling point.
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Which statement is true about the ionic size of the elements in a group as one moves from top to bottom in that group?
nekit [7.7K]

Answer:

Ionic size increases from top to bottom within the group.

Explanation:

  • Ions are formed when neutral atoms of elements gain or lose electron(s).
  • The ionic radius is the distance from the nucleus of an ion to the outermost energy level.
  • The ionic size or radius increases down the group as the number of energy level increases.
  • Therefore, an ion of an element lower in the group will be larger than the ion of an element higher in the group.
  • For example, an ion of potassium, K+, is larger in size compared to the ion of sodium, Na+ since K+ has more energy levels than Na+.
8 0
3 years ago
Read 2 more answers
By what factor would a scuba diver’s lungs expand if she ascended rapidly to the surface from a depth of 125 ft without inhaling
vova2212 [387]

It is found that scuba diver’s can safely ascend up to 52.53 ft without Breathing out.

By what factor would a scuba diver’s lungs expand if she ascended rapidly to the surface from a depth of 125 ft without inhaling or exhaling then

p_{1} =patm+pH_{2} O

p_{1} = 101325+ρgh_{1}

It is given that height is 125ft. Put the value of h in above formula:

h1  =125ft=38.1m

ρ=1.04g/mL=1040kg/m^{3}

g=9.81                                  

p_{1} =101325Pa+388711.44

p_{1}   =490036.44‬Pa                

p_{2} =p atm  =101325Pa

It is known that volume and pressure can be expressed as:

V*P=const.

where, V is volume and P is pressure.

Now,              

V_{1} *p_{1} =V_{2}  *p_{2}

V_{2} /V_{1}=p_{2} /p_{1}

V_{2} /V_{1} =490036.44/101325

V_{2} /V_{1}=4.84

Assume constant temperature

d of seawater = 1.04 g/mL; d of Hg = 13.5 g/mL.

now p_{1} =p atm​+pH_{2} O =490036.44Pa

V*p=const                              

where, V is volume and P is pressure.

Now,              

V_{1} *p_{1} =V_{2}  *p_{2}

V_{2} /V_{1}=p_{2} /p_{1}

V_{2} /V_{1} =490036.44/X

p_{2} =490036.44pa/(V2/V1) =326690.96Pa

p_{2} =patm +pH_{2} O

p_{2} =101325Pa+ρgh_{2}

326690.96Pa=101325Pa+ρgh_{2}

ρgh1  =151987.5-101325=225365.96‬‬Pa

ρ=1,04g/mL=1040kg/m3

g=9.81

h_{2} =225365.96/‬ρ∗g

​h_{2}  =225365.96  / ‬1040∗9.81

h_{2}  =22.09m= 72.47ft

ΔH=H_{1} -H_{2}

=125-72.47

=52.53ft

So she can safely ascend up to 52.53 ft without Breathing out

To know more about Scuba diver here

brainly.com/question/15430942

#SPJ4

6 0
1 year ago
Which of the following would increase the strength of an electromagnet? Check all that apply.
TiliK225 [7]

Answer: The correct statements are ; A and B.

Explanation:

The strength of the magnetic field(B) in an electromagnet can be calculated using formula:

B=\mu\frac{N}{L}I

\mu = Relative permeability

N = number of turns

I = Current in the wire of the solenoid

L = length of the solenoid or electromagnetic

As we can see from the formula:

B\propto N

B\propto I

So, by increasing the turns and increasing current flowing through wire one can increase the strength of an electromagnet.

Hence, the correct statements are ; A and B.

5 0
3 years ago
Need help with chemistry
Butoxors [25]

Answer:

Its the first second and the fourth

8 0
3 years ago
A rock weighing 32.0 g is placed in in a graduated cylinder displacing the volume from 22.3 mL to 27.6 mL. What is the density o
mojhsa [17]
27.6 - 22.3 = 5.3; you simply subtract the old density from the new density.
5 0
3 years ago
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