The acceleration of the train at the give initial and final velocity is determined as 10.5 m/s².
<h3>Acceleration of the train</h3>
The acceleration of the train is calculated as follows;
a = Δv/t
where;
- u is initial velocity = 162 km/hr = 45 m/s
- v is final velocity of the car = 540 km/hr = 150 m/s
a = (150 - 45)/10
a = 10.5 m/s²
Thus, the acceleration of the train at the give initial and final velocity is determined as 10.5 m/s².
Learn more about acceleration here: brainly.com/question/605631
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Explanation:
The charge (positive or negative) is always on the surface in the conductors. So, if the plates have substantial thickness, the charge is distributed throughout the surface. We know from the question that the bottom plate is charged positively, so an equal amount of negative charge must be distributed on the lower surface of the upper plate.
The direction of the E-field is always directed from positive to the negative charge. Since the plates have flat surfaces, the electric field lines are straight, except the edges. In most college level questions this effect is negligible, that is why in most questions the plates are considered very large.
<span>It is traveling at 10m/s.</span>
Convert the units of power,W = 7 hp = 7 * 745.69 = 5219.83 WCalculate the power input to the pump using the efficiency of the pump equationn=Wpump/Wshaft
Substitute 0.82 for n and 5219.83 for Wshaft0.82=Wpump/5219.83 Wpump=0.82*5219.83=4280.26 WCalculate the mass flow ratein=Wpump/(gz_2 )Where g is the acceleration due to gravity, and z_2 is the elevation of water. Substitute 4280.26 for Wpump, 9.81 m/s^2 for g, and 19m for z_2in = 4280.26 / 9.81 * 19 = 22.9640 m^3/sCalculate the volume flow rate of waterV=m/ρWhere ρ is the density of water. Substitute 22.9640 m^3/s for in and 1000 m^3/kg for ρ, we get V = 22.9640 / 1000 = 0.0230 kg/sTherefore, the volume flow rate of water is 0.0230 kg/s