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satela [25.4K]
3 years ago
6

You are a doctor and Jack is your patient. Jack wants to know about his overall health. What is the best thing you can do to hel

p Jack understand his overall health?
Determine his body composition

Look at his body build

Measure his body size

Obtain his body weight
Physics
1 answer:
Novay_Z [31]3 years ago
5 0

Answer:

determine his body composition

Explanation:

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OlgaM077 [116]

Answer: 18 m/s/s

Explanation:

3 times 6 equals 18 and 3 seconds every second makes this equation

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3 years ago
Hurryyy please helppp <br> Select all of the objects Found in our solar system
kipiarov [429]

Answer:  Star, planets, dwarf planets, comets, asteroids.

4 0
3 years ago
the motion of a particle along a straight line is represented by the position versus time graph above. at which of the labeled p
atroni [7]

Point A has the largest magnitude of acceleration as compared to other points on the position verses time graph.

On the graph, A is the point where magnitude of the acceleration of the particle is greatest as compared to other positions on the graph because the height of point A is the largest as compared to other points of the graph.

The graph shows at which point acceleration of an object is higher and lower so we can conclude that point A has the largest magnitude of acceleration as compared to other points on the position verses time graph.

Learn more about acceleration here: brainly.com/question/933224

Learn more: brainly.com/question/25887663

3 0
2 years ago
Halley's comet orbits the sun roughly once every 76 years. It comes very close to the surface of the Sun on its closest approach
Licemer1 [7]

Answer:

r1 = 5*10^10 m , r2 = 6*10^12 m

v1 = 9*10^4 m/s

From conservation of energy

K1 +U1 = K2 +U2

0.5mv1^2 - GMm/r1 = 0.5mv2^2 - GMm/r2

0.5v1^2 - GM/r1 = 0.5v2^2 - GM/r2

M is mass of sun = 1.98*10^30 kg

G = 6.67*10^-11 N.m^2/kg^2

0.5*(9*10^4)^2 - (6.67*10^-11*1.98*10^30/(5*10^10)) = 0.5v2^2 - (6.67*10^-11*1.98*10^30/(6*10^12))

v2 = 5.35*10^4 m/s

3 0
3 years ago
A weightlifter curls a 32 kg bar, raising it each time a distance of 0.50 m. How many times must he repeat this exercise to burn
strojnjashka [21]

Answer:

Explanation:

Average energy contained by  a slice of pizza is 860 J  .

energy used in lifting 32 kg bar by .50 m = mgh

= 32 x 9.8 x .5 = 156.8 J

efficiency is 25 % , so energy used up = .75 x 156.8 = 117.6 J

So number of times exercise to be repeated to burn off energy of a slice of pizza

= 860 / 117.6

= 7.3 or 7 times .

4 0
3 years ago
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