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Leni [432]
4 years ago
13

Longitudinal waves have _____.

Physics
2 answers:
tino4ka555 [31]4 years ago
7 0
<span>Longitudinal waves have _____.

</span>
<span>D. compressions and rarefactions </span>
Yakvenalex [24]4 years ago
6 0
I think its either C or D. I tried, couldn't figure the last part out. Hope this helped though!! Have a great day! :D
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If the scaled-up man now stands on one leg, what fraction of the tensile strength is the stress on the femur?.
Oksanka [162]

The fraction of the tensile strength which is the stress on the femur is 1.4%.

<h3>What is Tensile strength?</h3>

This is defined as the amount of load or stress that a material can handle before it stretches and breaks.

The femur which is located in the thigh is the largest bone in the body and it exerts a fraction of 1.4% tensile strength through the stress encountered on the femur when the man stands with one leg.

Read more about Tensile strength here brainly.com/question/25748369

5 0
2 years ago
a ball is thrown straight up it passes a 2.00 m high window 7.5 meters off the ground on its path up it takes 1.3 s to go past t
Svet_ta [14]
Let's say the velocity at the bottom of the window was "v."
s = v*t + ½at²
2 m = v * 1.3s - 4.9m/s² * (1.3s)² = v * 1.3s - 8.3 m
v = 10.3m / 1.3s = 7.9 m/s

Then the initial speed was
V = √(v² + 2as) = √(7.9m/s² + 2 * 9.8m/s² * 7.5m) = 14 m/s ◄ initial velocity
(after rounding to 2 digits from 14.5 m/s).
8 0
3 years ago
PLS HELP BEING TIMED!!!
Elodia [21]

Answer:

K_{i}+U_{g,i} = K_{f}+U_{g,f}

Explanation:

A closed system is a system where exists energy interactions with surroundings, but not mass interactions. If we neglect any energy interactions from boundary work, heat, electricity, magnetism and nuclear phenomena and assume that process occurs at steady state and all effects from non-conservative forces can be neglected, then the equation of energy conservation is reduce to this form:

\Delta K +\Delta U_{g} = 0 (1)

Where:

\Delta K - Change in kinetic energy of the system, measured in joules.

\Delta U_{g} - Change in gravitational potential energy of the system, measured in joules.

If we know that \Delta K=K_{i}-K_{f} and \Delta U_{g} = U_{g,i}-U_{g,f}, then we get the following equation:

K_{i}+U_{g,i} = K_{f}+U_{g,f} (2)

Where i and f stands for initial and final states of each energy component.

Hence, the right answer is K_{i}+U_{g,i} = K_{f}+U_{g,f}

7 0
3 years ago
Read 2 more answers
Unpolarized light passes through a vertical polarizing filter, emerging with an intensity I0. The light then passes through a ho
antiseptic1488 [7]

To solve this problem it is necessary to apply the concepts related to Malus' law. Malus' law indicates that the intensity of a linearly polarized ray of light that passes through a perfect analyzer with a vertical optical axis is equivalent to:

I = I_0 cos^2(\theta)

I_0 = Indicates the intensity of the light before passing through the Polarizer,

I = The resulting intensity, and

\theta = Indicates the angle between the axis of the analyzer and the polarization axis of the incident light.

There is 3 polarizer, then

For the exit of the first polarizer we have that the intensity is,

I_2 = I_0cos^2(45)

For the third polarizer then we have,

I_3 = I_2 cos^{2}(45)

Replacing with the first equation,

I_3 =  I_0cos^2(45)cos^{2}(45)

I_3 = I_0 (\frac{1}{2})(\frac{1}{2})

I_3 = I_0 \frac{1}{4}

Therefore the transmitted intensity now is \frac{1}{4} of the initial intensity.

5 0
4 years ago
Astronomers study radio waves to learn about
il63 [147K]

Answer:

Radio astronomy began in 1933 when an engineer named Karl Jansky accidentally discovered that radio waves come not just from inventions we create but also from natural stuff in space.

3 0
4 years ago
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