A parallel circuit has multiple paths from the energy source to the resistors (e.x., lightbulbs). If one bulb was to burn out, the rest would stay on, unlike a series circuit. If one bulb was to burn out, the circuit is no longer fully connected because there is only one path from the energy source to the resistors. But, despite these differences, they are similar in the way that they do have paths from the energy source to the resistors.
Answer:
The answer is C. anti social
Explanation:
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Question #1:
a). The sketch is attached to this answer.
b). The equivalent resistance of 30Ω and 50Ω in parallel is
1 / (1/30 + 1/50) =
18.75 Ωc). I = V/R = (100/30) =
(3 and 1/3) Amperesd). Follow the wires, and you see that the 50Ω resistor is
connected directly to the battery, and so is the voltmeter.
So the voltage across the 50Ω resistor, and the reading
on the voltmeter, is
100 volts.e). I = V/R
Through the 30Ω resistor: I = 3-1/3 A
Through the 50Ω resistor: I = 2 A
f). In the parallel circuit, both resistors are connected
directly to the battery. So neither resistor even knows
that the other one is there.
Each resistor sees 100 volts,
and the current through each resistor is 100/R, just as if
it were the only resistor in the circuit.
Based on your question where a car leaves skid marks 85m long on the highway nad getting to stop. The deceleration of the car is 3m/s^2 to estimate the speed of the car just before braking first is to analyze the problem then apply the necessary formulas. the possible answer is 510m/s