2 NaCl --------> 2 Na + Cl₂
2 mol * 23 g Na = 46 g
2*35,5 g Cl = 71
46 g Na --------- 71 g Cl₂
460 g Na -------- ?
mass ( Cl₂) = 460 . 71 / 46
Mass (Cl₂) = 32660 / 46
m= 710 g of Cl₂
<span>hope thips helps</span>
Answer:
Explanation:
Molar mass of KF= 39 + 19= 58g/mol
Mass of KF = 109g
Amount = mass/molar mass
Amount = 109/58
Amount = 1.9moles
Original molarity was 1.7 moles of NaCl
Final molarity was 0.36 moles of NaCl
Given Information:
Original (concentrated) solution: 25 g NaCl in a 250 mL solution, solve for molarity
Final (diluted) solution: More water is added to make the new total volume 1.2 liters, solve for the new molarity
1. Solve for the molarity of the original (concentrated) solution.
Molarity (M) = moles of solute (mol) / liters of solution (L)
Convert the given information to the appropriate units before plugging in and solving for molarity.
Molarity (M) = 0.43 mol NaCl solute / 0.250 L solution = 1.7 M NaCl (original solution)
2. Solve for the molarity of the final (diluted) solution.
Remember that the amount of solute remains constant in a dilution problem; it is just the total volume of the solution that changes due to the addition of solvent.
Molarity (M) = 0.43 mol NaCl solute / 1.2 L solution
Molarity (M) of the final solution = 0.36 M NaCl
I hope this helped:))
I believe it is C
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To calculate<span> the average </span>atomic mass<span>, multiply the fraction by the </span>mass<span> number for each isotope, then add them together.</span>