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lora16 [44]
3 years ago
5

State two essential conditions for rusting of iron. List two methods of protecting iron from rusting?​

Chemistry
1 answer:
gizmo_the_mogwai [7]3 years ago
8 0
Conditions for rusting
• moisture
•oxygen

Prevention
•Painting
• Galvanisation
• Making Alloys
• greasing
Hope this helps you ;)(:

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A 1170.-gram sample of NaCl() completely reacts, producing 460. grams of Na(). What is the total mass of Cl2(g) produced?
777dan777 [17]
2 NaCl --------> 2 Na  + Cl₂
  
2 mol * 23 g Na = 46 g

2*35,5 g Cl = 71 

 46 g Na --------- 71 g Cl₂
 460 g Na -------- ?

mass ( Cl₂) = 460 . 71 / 46

Mass (Cl₂) = 32660 / 46

m= 710 g of Cl₂

<span>hope thips helps</span>
4 0
3 years ago
How many moles are in 109 grams of kf
lions [1.4K]

Answer:

Explanation:

Molar mass of KF= 39 + 19= 58g/mol

Mass of KF = 109g

Amount = mass/molar mass

Amount = 109/58

Amount = 1.9moles

4 0
3 years ago
If a sample of sodium chloride with a mass of
alex41 [277]
Original molarity was 1.7 moles of NaCl

Final molarity was 0.36 moles of NaCl

Given Information:

Original (concentrated) solution: 25 g NaCl in a 250 mL solution, solve for molarity

Final (diluted) solution: More water is added to make the new total volume 1.2 liters, solve for the new molarity

1. Solve for the molarity of the original (concentrated) solution.

Molarity (M) = moles of solute (mol) / liters of solution (L)

Convert the given information to the appropriate units before plugging in and solving for molarity.

Molarity (M) = 0.43 mol NaCl solute / 0.250 L solution = 1.7 M NaCl (original solution)

2. Solve for the molarity of the final (diluted) solution.

Remember that the amount of solute remains constant in a dilution problem; it is just the total volume of the solution that changes due to the addition of solvent.

Molarity (M) = 0.43 mol NaCl solute / 1.2 L solution

Molarity (M) of the final solution = 0.36 M NaCl

I hope this helped:))
6 0
3 years ago
Which one????? Please help me
Strike441 [17]
I believe it is C

The definition of wafting is: "<span>pass or cause to pass easily or gently through or as if through the air."</span>
6 0
3 years ago
How to find an elements atomic weight
Tju [1.3M]
To calculate<span> the average </span>atomic mass<span>, multiply the fraction by the </span>mass<span> number for each isotope, then add them together.</span>
3 0
3 years ago
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