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Alja [10]
2 years ago
5

Mrs. Nogaki tested four black markers in rubbing alcohol and in water. Each filter paper had four evenly spaced dots. She found

that all four markers had ink that separated into two or more different pigments when placed in the rubbing alcohol. What was her dependent variable?
Chemistry
1 answer:
ExtremeBDS [4]2 years ago
8 0

Answer:

Lost pigment of marker when dipped in alcohol

Explanation:

dependent viable = output

so it's the output of what happens after the input.

  • she put the marker in the water which is the independent variable, that's the input
  • the output or the result of that decision is having lost pigment in the marker

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I WILL DIE I HAVE A KNIFE IN MY HAND. ANSWER WITH EXPLANATION. If the sound is high pitched, then the wave's frequency would hav
enyata [817]

Answer:

Option A - High frequency, short wavelength.

Explanation:

<em>If the sound is high then the frequency is also high but short-wavelength means lots of waves that always have a high pitch-sound and a high frequency. </em>

3 0
3 years ago
The standard enthalpy of formation for glucose [c6h12o6(s)] is −1273.3 kj/mol. what is the correct formation equation correspond
balu736 [363]
The standard formation equation for glucose C6H12O6(s) that corresponds to the standard enthalpy of formation or enthalpy change ΔH°f = -1273.3 kJ/mol is 
     C(s) + H2(g) + O2(g) → C6H12O6(s)
and the balanced chemical equation is 
     6C(s) + 6H2(g) + 3O2(g) → C6H12O6(s)

Using the equation for the standard enthalpy change of formation 
     ΔHoreaction = ∑ΔHof(products)−∑ΔHof(Reactants)
     ΔHoreaction = ΔHfo[C6H12O6(s)] - {ΔHfo[C(s, graphite) + ΔHfo[H2(g)] + ΔHfo[O2(g)]}

C(s), H2(g), and O2(g) each have a standard enthalpy of formation equal to 0 since they are in their most stable forms:
     ΔHoreaction = [1*-1273.3] - [(6*0) + (6*0) + (3*0)]
                           = -1273.3 - (0 + 0 + 0)
                           = -1273.3
8 0
3 years ago
A perfect cube of aluminum metal was found to weigh 20.00 g. The density of aluminum is 2.7 g/ml. What are the dimensions of the
denis23 [38]

Answer:

             Height  = 1.9493 cm

             Width =  1.9493 cm

             Depth  =  1.9493 cm

Solution:

Data Given:

                  Mass  =  20 g

                  Density  =  2.7 g/mL

Step 1: Calculate the Volume,

As,

                                        Density  =  Mass ÷ Volume

Or,

                                        Volume  =  Mass ÷ Density

Putting values,

                                        Volume  =  20 g ÷ 2.7 g/mL

                                        Volume  =  7.407 mL or 7.407 cm³

Step 2: Calculate Dimensions of the Cube:

As we know,

                                        Volume  =  length × width × depth

So, we will take the cube root of 7.407 cm³ which is 1.9493 cm.

Hence,

                                        Volume  =  1.9493 cm × 1.9493 cm × 1.9493 cm

                                        Volume  =  7.407 cm³

4 0
3 years ago
What is the process by which sand dunes occur?
Arte-miy333 [17]
B............................................................................
3 0
3 years ago
What is the total number of valence electrons un xenon(xe)
Ber [7]

Answer:

8

Explanation:

Hope this helps you :)

6 0
2 years ago
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