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Alisiya [41]
2 years ago
7

Help pleased alot of points​

Chemistry
1 answer:
JulsSmile [24]2 years ago
4 0

Answer:

Nitrogen non metal

Gain 3 electrons

Negative ion N3-

Barium metal

Lose electrons

Positive charge

Selinium non metal

Gain electron

Negative charge

Cesium metal

Lose electrons

Positive charge

Explanation:

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Click on the event or events that led to the formulation of the cell theory
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So back in 1665 Robert hook was able to view cells and describe them along with pictures, the reason he was able to see cells was because the microscope was invented a bit before, which allowed him to think about things differently, he was looking at a cork and saw squared objects, these objects were cells, according to him.

So while the cork was the reason he discovers cells on it in the first place,
The microscope was what allowed him to do that

So it’s (HOOKE LOOKING AT A CORK)
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A volume of 129 mL of hydrogen is collected over water. The water level in the collecting vessel is the same as the outside leve
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Explanation:

As it is given that water level is same as outside which means that theoretically, P = 756.0 torr.

So, using ideal gas equation we will calculate the number of moles as follows.

                  PV = nRT

or,           n = \frac{PV}{RT}

                 = \frac{\frac{756}{760}atm \times 0.129 L}{0.0821 Latm/mol K \times 298 K}

                  = 0.0052 mol

Also,  No. of moles = \frac{mass}{\text{molar mass}}

               0.0052 mol = \frac{mass}{2 g/mol}

                  mass = 0.0104 g

As some of the water over which the hydrogen gas has been collected is present in the form of water vapor. Therefore, at 25^{o}C

                P_{\text{water vapor}} = 24 mm Hg

                                = \frac{24}{760} atm

                                = 0.03158 atm

Now,   P = \frac{756}{760} - 0.03158

              = 0.963 atm

Hence,   n = \frac{0.963 atm \times 0.129 L}{0.0821 L atm/mol K \times 298 K}

                 = 0.0056 mol

So, mass of H_{2} = 0.0056 mol × 2

                         = 0.01013 g (actual yield)

Therefore, calculate the percentage yield as follows.

      Percent yield = \frac{\text{Actual yield}}{\text{Theoretical yield}} \times 100

                              = \frac{0.01013 g}{0.0104 g} \times 100            

                              = 97.49%

Thus, we can conclude that the percent yield of hydrogen for the given reaction is 97.49%.

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