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patriot [66]
3 years ago
9

Improper use of cleaning agents in food-contact areas can add which of the following to food?

Chemistry
2 answers:
Black_prince [1.1K]3 years ago
7 0

The answer is A glass, meetal, insects and dirt ...found it in my textbook


Nikitich [7]3 years ago
5 0
I think the correct answer would be direct additives. Not proper handling of cleaning agents especially in areas where food are prepared or served would most likely add chemicals to the food which is harmful to the consumer. Hope this helps.
You might be interested in
Convert 16.8 L of nitrogen monoxide gas at STP to grams .
german

Answer:

See explanation

Explanation:

1 mole of a gas occupies 22.4 L

x moles occupies 16.8 L

x = 1 mole *  16.8 L/22.4 L

x = 0.75 moles

number of moles = mass/molar mass

mass =  number of moles  * molar mass

mass =  0.75 moles * 30.01 g/mol = 22.5075 g = 2.25 * 10^1 g

the coefficient of the scientific notation answer = 2.25

the exponent of the scientific notation answer = 1

significant figures are there in the answer = 6

the right most significant figure in the answer = 3

2.

number of moles = 12.5g/38g/mol = 0.3289 moles

1 mole occupies 22.4 L

0.3289 moles occupies 0.3289 moles * 22.4 L/1 mole

= 7.36736 L = 7.36736 * 10^0 L= 7.37 * 10^0 L

the coefficient of the scientific notation answer =7.37

the exponent of the scientific notation answer = 0

significant figures are there in the answer = 6

the right most significant figure in the answer= 3

8 0
3 years ago
Which definition best describes global warming?
Marat540 [252]

Answer:

answer:-

a long-term increase in the Earth's average temperature

4 0
3 years ago
Read 2 more answers
30 its ASAP!!!! What is the volume, in liters, occupied by 0.485 moles of Oxygen gas at 23.0 oC and 0.980 atm?
USPshnik [31]
Use the universal gas formula

PV=nRT
where
P=pressure ( 0.980 atm)
V=volume (L)
T=temperature ( 23 ° C = 23+273.15 = 296.15 ° K)
n=number of moles of ideal gas (0.485 mol)
R=universal gas constant = <span>0.08205 L atm / (mol·K)

Substitute values,
Volume, V (in litres)
=nRT/P
=0.485*0.08205*296.15/0.980
= 12.0256 L
= 12.0 L (to three significant figures)

</span>
5 0
3 years ago
The US mail delivery considered a network true or false
Svetllana [295]
True
Hope this helps!!❤️
6 0
3 years ago
The chemical equation below shows the combustion of methane (CH4).
STatiana [176]
The correct answer is 6.15g of CO2 will be produced.

The approach to answer this question is to use the molar mass to find the number of moles of oxygen consumed. Then use the chemical equation to determine the number of moles of CO2 that would be produced (half that of oxygen). Then use the molar mass of CO2 to calculate the mass.

Mmass O2 = 32g/mol
Mmass CO2 = 44.01g/mol
mass O2 consumed = 8.94g
mass CO2 produced = ?

moles O2 = mass / molar mass = 8.94 / 32 = 0.279
moles CO2 = half that of O2 = 0.1397

mass CO2 produced = moles CO2 x molar mass = 0.1397 x 44.01 = 6.15 g

:)




6 0
4 years ago
Read 2 more answers
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