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mestny [16]
3 years ago
10

1. What operation is being used in the equation? x + 15 = 22

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
5 0
Property of addition I think
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Eva8 [605]

Answer:38

Step-by-step explanation:multiple

5 0
3 years ago
What steps to get the answer for -4x+7=11
tiny-mole [99]

Answer:

-4x=4

Step-by-step explanation:

-4x+7=11 subtract 7 add to the 11 answer-4x=4

5 0
3 years ago
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Which of the given pairs of expressions are equivalent? Select all that apply.
Artyom0805 [142]

Answer:

sorry I don't know about this Question

8 0
3 years ago
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I Need help with 4-7
Murrr4er [49]

Answer:

Step-by-step explanation:

4) parallel because 118° is a supplement to 62° and the corresponding angles are both 118°

5) NOT parallel. The labeled angles sum to 120° and would sum to 180° for parallel lines.

6) NOT parallel. see pic.

If parallel, extending a line to intersect ℓ₁ makes an opposite internal angle which would also be 48°. The created triangle would have its third angle at 180 - 90 - 48 = 42° which is opposite a labeled 48° angle, which is false, so the lines cannot be parallel

7)

b = 78°  as it corresponds with a labeled angle above it

a = 180 - 78 = 102° as angles along a line from a common vertex sum to 180

f = is an opposite angle to 180 - 78 - 44 = 58° as angles along a line from a common vertex sum to 180

e = 180 - 90 - 64 = 26° as angles along a line from a common vertex sum to 180

c = 58° as it corresponds with f

d = 180 - 58 = 122° as angles along a line from a common vertex sum to 180

 

4 0
3 years ago
In a string of 12 Christmas tree light bulbs, 3 are defective. The bulbs are selected at random and tested, one at a time, until
Juliette [100K]

Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

In this problem:

  • There are 12 bulbs, hence N = 12.
  • 3 are defective, hence k = 3.

The third defective bulb is the fifth bulb if:

  • Two of the first 4 bulbs are defective, which is P(X = 2) when n = 4.
  • The fifth is defective, with probability of 1/8, as of the eight remaining bulbs, one will be defective.

Hence:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,12,4,3) = \frac{C_{3,2}C_{9,1}}{C_{12,4}} = 0.2182

0.2182 x 1/8 = 0.0273.

0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

8 0
2 years ago
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