Answer:
Explanation:
a )
While breaking initial velocity u = 62.5 mph
= 62.5 x 1760 x 3 / (60 x 60 ) ft /s
= 91.66 ft / s
distance trvelled s = 150 ft
v² = u² - 2as
0 = 91.66² - 2 a x 150
a = - 28 ft / s²
b ) While accelerating initial velocity u = 0
distance travelled s = .24 mi
time = 19.3 s
s = ut + 1/2 at²
s is distance travelled in time t with acceleration a ,
.24 = 0 + 1/2 a x 19.3²
a = .001288 mi/s²
= 2.06 m /s²
c )
If distance travelled s = .25 mi
final velocity v = ? a = .001288 mi / s²
v² = u² + 2as
= 0 + 2 x .001288 x .25
= .000644
v = .025 mi / s
= .0025 x 60 x 60 mi / h
= 91.35 mph .
d ) initial velocity u = 59 mph
= 86.53 ft / s
final velocity = 0
acceleration = - 28 ft /s²
v = u - at
0 = 86.53 - 28 t
t = 3 sec approx .
Ans) A) Centripetal force will be doubled.
See centripetal force F = mv^2/r
That means centripetal force is directly proportional to the mass of the particle
So, if we double the mass, centripetal force will be increased by twofolds.
So, option A) is correct.
Now, looking at the other options,
B) says centripetal force is unaltered which is incorrect as centripetal force has been altered and increased twofold.
Option C) and D) reduces centripetal force which are also not possible here.
So, only Option A) is correct
The starting point for measuring motion is called : The Reference Point.
Answer:
reaching a speed of 30 meters per second in 6 seconds.
During the 6 seconds, the car has traveled
a distance of
1. 180 m
2. 60 m
3. 15 m
4. 30 m
5. 90 m
Explanation:
