Answer:
The stiffness of one of the individual spring is 390 N/m.
Explanation:
It is given that 43 identical springs are placed side-by-side and connected to a large massive block.
The stiffness of the 43 spring combination is 16770 N/m
We need to find the stiffness of one of the individual springs. Let k is the stiffness of one spring. The effective spring stiffness of this width spring is given by :
k = 390 N/m
So, the stiffness of one of the individual spring is 390 N/m. Hence, this is the required solution.
Answer:
Gravity and
Air resistance
Explanation:
The two forces acting on a skydiver are gravitational force and air resistance.
Gravitational force is a force that tends to pull all massive bodies towards the center of the earth. It works on all bodies that has mass. The larger or bigger the mass, the more the pull of gravity on the body.
Air resistance is the drag of air on a body as it passes to it. It is resisting force.
- When a sky diver jumps out of a plane, he/she encounters both gravity and air resistance.
- It soon balances both force and attain terminal velocity.
- Air resistance is a frictional force that opposes motion.
- This frictional force pushes in the opposite direction of motion
- Motion direction is downward due to the celerity caused by gravity.
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Responder:
35,2 ohm.
Explicación:
Dado:
La resistencia específica del conductor es,
La longitud del conductor es,
El área de la sección transversal del conductor es,
Sabemos que la resistencia de un conductor es directamente proporcional a su longitud e inversamente proporcional al área de la sección transversal.
Por lo tanto, la resistencia se puede expresar como:
Ahora, conecte los valores dados y resuelva para 'R'. Esto da,
Por lo tanto, la resistencia del conductor es de 35,2 ohm.
Answer:
<h3>The answer is 0.47 kg</h3>
Explanation:
The mass of the object given it's momentum and velocity can be found by using the formula
where
p is the momentum
v is the velocity
We have
We have the final answer as
<h3>0.47 kg</h3>
Hope this helps you
