Ask question

Ask question

All categories

4 years ago

10

1. what is the average velocity of a car if it travels from position 25 m to a position of -7 m in 34 seconds ?

1 answer:

zubka84 [21]4 years ago

5 0

1.

x₀ = initial position of the car = 25 m

x = final position of the car = - 7 m

t = time taken by the car = 34 seconds

displacement of the car is given as

d = change in position = x - x₀ = - 7 - 25 = - 32 m

average velocity of the car is given as

V = d/t

V = - 32/34

V = - 0.94 m/s

2.

after the rock is thrown up in air , the only force acting on the rock is force of gravity in down direction. due to this force , the rock experience acceleration in down direction which is known as the acceleration due to gravity. the magnitude of this acceleration is constant and is given as 9.8 m/s²

You might be interested in

What is the angular velocity of the door just after impact?

Dmitry [639]

What impact ? Is there more to this question so I can help answer ?

5 0

4 years ago

What is the upper block's acceleration if the coefficient of kinetic friction between the block and the table is 0.13?

IgorLugansk [536]

Let us assume that pulley is mass less.

Let the tension produced at both ends of the pulley is T.

We are asked to calculate the acceleration of the block.

Let the masses of two bodies are denoted as $m_{1} \ and\ m_{2}\ respectively$

$Let\ m_{1} =1 kg\ and\ m_{2} =2 kg$

As per this diagram, the body having mass 1 kg is moving downward and the body having mass 2 kg is moving on the surface of the table.

Let the acceleration of each block is a .

For body having mass 1 kg:

The net force acting on 1 kg body will be-

$m_{1} g-T=m_{1} a$ [1]

Here tension in the rope will be vertically upward and weight of the body will be in vertical downward direction.

For body having mass 2 kg:

The coefficient of kinetic friction $[\mu]=0.13$

$Hence\ the\ frictional\ force\ F=\mu N$

$F=\mu m_{2} g$

Hence the net force acting on the body having mass 2 kg-

$T-\mu m_{2} g=m_{2} a$ [2]

Here the tension of the rope is towards right i.e along the direction of motion of the 2 kg block and frictional force is towards left.

Combining 1 and 2 we get-

$m_{1} g-T=m_{1}a$ [1]

$T-\mu m_{2}g= m_{2} a$ [2]

---------------------------------------------------

$[m_{1} -\mu m_{2} ]g=[m_{1} +m_{2} ]a$

$a=\frac{m_{1}-\mu m_{2}} {m_{1}+ m_{2}}*g$

$a=\frac{1-[2*0.13]}{1+2} *9.8\ m/s^2$

$a=\frac{0.74}{3} *9.8\ m/s^2$

$a=2.417 m/s$ [ans]

6 0

3 years ago

Read 2 more answers

In mantle convection currents, hotter rock moves _______, while cooler rock moves _______. downward; upward upward; downward sid

diamong [38]

<span>In mantle convection currents, hotter rock moves __upward_____, while cooler rock moves __downward_____.</span>

6 0

4 years ago

Read 2 more answers

When a sound source is moving away from an observer, the observer will hear a lower pitch. This is due to

iren2701 [21]

Lower Pitch Due to the change to a lower frequency

7 0

3 years ago

Read 2 more answers

I need help with this

Tema [17]

Explanation in File!

6 0

3 years ago