When a pair of 10-n forces act on a box of candy, the net force on the box is?
2 answers:
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Answer:
The correct option is;
(c) 64W
Explanation:
Here we have the Coefficient Of Performance, COP given by
The heat change from 23° to 6°C for a mass of 10 kg/h which is equivalent to 10/(60×60) kg/s or 2.78 g/s we have
= m·c·ΔT = 2.78 × 4.18 × (23 - 6) = 197.39 J
Therefore, plugging in the value for in the COP equation we get;
which gives
Since we were working with mass flow rate then the power input is the same as the work done per second and the power input to the refrigerator = 63.674 J/s ≈ 64 W.
The power input to the refrigerator is approximately 64 W.
Answer:
The answer is a=b=c=3.833 cm
Explanation:
Lets call the variables a=side a b=side b c=side c
We have that the formula of the equilateral triangle for its height is:
1)h=(1/2)*root(3)*a
2) If we resolve the equation we have
2.1)2h=root(3)*a
2.2)(2h/root(3))=a
3) After the replacement of each value we have that
a=2*3.32/1.73205
a=3.833 cm
And we know that the equilateral triangle has the same value for each side so a=b=c=3.833 cm
