A motorcyclist sees a branch in the road, and hits the brakes, slowing down at -6.42 m/s^2. If it takes him 2.85 s to stop, what
was his starting velocity?
1 answer:
Answer:
his starting velocity was 18.297 ms⁻¹
Explanation:
v = u + at .................. (1)
Where
Final Velocity (v) = 0 ms⁻¹
Initial velocity (u) = ?
Acceleration (deceleration) (a) = -6.42 ms⁻²
time (t) = 2.85 s
Substituting all parameters into equation (1)
0 = u + (-6.42)2.85
0 = u + (-18.297)
0 = u - 18.297
18.297 = u
∴ the initial velocity was 18.297 ms⁻¹
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