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belka [17]
3 years ago
13

If the vapour pressure of

Chemistry
1 answer:
lawyer [7]3 years ago
8 0

Answer:

b 0.027 atm

Explanation:

It is possible to solve this question using Raoult's law that says that the partial pressure of each component of an ideal mixture of liquids is equal to the vapour pressure of the pure component multiplied by its mole fraction in the mixture.

To know mole fraction of water you need to know how many moles of water have 1L. Moles are:

1L × (1000g/1L) × (1mol/18,01g) = <em><u>55,5 moles of water</u></em>.

Mole fraction is:

55,5 moles of water / (55,5+5) total moles = <em><u>0,917</u></em>

Thus, vapour pressure of the solution is:

0,917 × 0,03atm = <em>0,027atm</em>

Right answer is:

<em>b 0.027 atm </em>

<em></em>

I hope it helps!

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Name the element described in each of the following:
borishaifa [10]

Alkaline earth metal whose cation isoelectric with Kr is strontium (Sr).

What is Alkaline earth metal?

Six chemical elements from group 2 of the periodic chart make up the alkaline earth metals. They are boron (R), barium (Ba), calcium (Ca), strontium (Sr), magnesium (Mg), beryllium (Be), and radium (Ra). The elements share many characteristics, including being glossy, silvery-white, moderately reactive metals at standard pressure and temperature.

They share a full outer s-orbital structurally, meaning that this orbital includes all two of its electrons, which the alkaline earth metals rapidly lose to form cations with a charge of +2 and an oxidation state of +2.

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8 0
2 years ago
Whats the si unit chemist use to measure the amount of an element substance?
Westkost [7]
The SI unit for the amount of substance present is the mole.

The mole is defined as the amount of substance that has the same amount of particles as there are atoms in 12 grams of carbon-12. Mathematically, the moles of a substance may be computed using:

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4 0
3 years ago
At a cost of $1600/oz, how much would you have to pay for a solid cubic foot of gold?
Alex777 [14]
<h3>You will pay $ 30876800</h3>

We'll begin by calculating the mass in ounce (oz) of a cube foot (ft³) of gold. This can be obtained as follow:

<h3 />

Density of gold = 19298 oz/ft³

Volume of gold = 1 ft³

<h3>Mass of gold =?</h3>

Density = mass /volume

19298 = mass / 1

<h3>Mass of gold = 19298 oz</h3>

Finally, we shall determine the cost of 19298 oz of gold. This can be obtained as follow:

1 oz = $ 1600

Therefore,

19298 oz = 19298 × 1600

19298 oz = $ 30876800

Therefore, a solid cube foot of gold (i.e 19298 oz) will cost $ 30876800

Learn more: brainly.com/question/15407624

4 0
3 years ago
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