Question

When blue light of wavelength 470 nm falls on a single slit, the first dark bands on either side of center are separated by 51.0 ?. Determine the width of the slit. Express your answer to three significant figures and include the appropriate units.

Answer 1

Answer:

The width of the slit is $3.51\times10^{-7}\ m$.

Explanation:

Given that,

Wavelength = 470 nm

Angle = 51.0°

We need to calculate the width of slit

Using formula of width

$2d\sin\theta=n\lambda$

$d=\dfrac{n\lambda}{2\sin\theta}$

Where, n = number of fringe

$\lambda$ = wavelength

Put the value into the formula

$d=\dfrac{1\times470\times10^{-9}}{2\sin51}$

$d=3.51\times10^{-7}\ m$

Hence, The width of the slit is $3.51\times10^{-7}\ m$.