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juin [17]
3 years ago
7

A 0.145 kg baseball is thrown horizontally at 15 m/s from a platform, so that it starts at 5.2 m above the ground. How much has

its kinetic energy increased when it reaches the ground? 16 J , 24 J , 0 J , or 7.4 J ? :/
Physics
1 answer:
fomenos3 years ago
6 0
7.4J
final kinetic energy
= initial potential energy
= mass x gravitational force x height
= 0.145 x 9.81 x 5.2
= 7.39674 J
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sergejj [24]

This question is incomplete, the complete question is;

A football quarterback throws a 0.408 kg football for a long pass. While in the motion of throwing, the quarterback moves the ball 1.909 m, starting from rest, and completes the motion in 0.439 s. Assuming the acceleration is constant, what force does the quarterback apply to the ball during the pass ;

a) F_throw = 8.083 N

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c) F_throw = 2.284 N

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e) None of these is correct

Answer:

the quarterback applied a force of 8.083 N to the ball during the pass

so Option a) F_throw = 8.083 N is the correct answer

Explanation:

Given that;

m = 0.408 kg

d = 1.909 m

u = 0 { from rest}

t = 0.439 s

Now using Kinetic equation

d = ut + 1/2 at²

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1.909 = (0 × 0.439) + 1/2 a(0.439)²

1.909 = 0 + 0.09636a

1.909 = 0.09636a

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F = ma

we substitute

F = 0.408 ×  19.8111

F = 8.0828 ≈ 8.083 N

Therefore the quarterback applied a force of 8.083 N to the ball during the pass

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4 years ago
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Answer:

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(a)

Using,

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(b)

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Substitute into equation 2

0 = 8+(-1.6t)

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