Question

Find the mass of AlCl3 that is produced when 25.0 grams of Al2O3 react with excess HCl according to the following equation.

Answer 1

Answer:

Mass = 65.4 g

Explanation:

Given data:

Mass of Al₂O₃ = 25 g

Mass of AlCl₃ = ?

Solution:

Chemical equation:

Al₂O₃ + 6HCl  →   2AlCl₃ + 3H₂O

Number of moles of Al₂O₃:

Number of moles = mass/ molar mass

Number of moles = 25 g/  101.96 g/mol

Number of moles = 0.2452 mol

Now we will compare the moles of Al₂O₃  and AlCl₃.

                          Al₂O₃         :            AlCl₃

                              1             :               2

                             0.2452    :          2×0.2452 = 0.4904 mol

Mass of AlCl₃:

Mass = number of moles × molar mass

Mass = 0.4904 mol × 133.34 g/mol

Mass = 65.4 g