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snow_tiger [21]
3 years ago
6

How to find magnitude of net electric charge when current flows through a capacitor with initial charge?

Engineering
1 answer:
Ksenya-84 [330]3 years ago
3 0

Answer:

Q=qe^{-t/RC}

also

q=it

Explanation:

How to find magnitude of net electric charge when current flows through a capacitor with initial charge?

A capacitor is a device used in storing electric charges. The unit of capacitance is measured in farad

To find the magnitude of net electric charge in a capacitor, we use the following relation

Q=qe^{-t/RC}

Q=the magnitude of net electric charge in coulombs

t=the time for an electron tpo pass through the capacitor

R=the resistance of the capacitor , measured in ohms

C=the capacitance of the capacitor measures in Farad

q=initial quantity of charge

Having all the parameters above will make it possible to determine the net electric charge

Recall also that

q=it

quantity (coulombs)=current*time(s)

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one number is 11 more than another number. find the two number if three times the larger number exceeds four times the smaller n
vaieri [72.5K]

Answer:

a = 40

b = 29

Explanation:

Give a place holder for the numbers that we don't know.

Lets call the two numbers a and b.

From the given info, we can write an expression and solve it:

"one number is 11 more than another number"

a = 11 + b

from this, we know that a > b.

''three times the larger number exceeds four times the smaller number by 4"

3a = 4b + 4

Now we have 2 equations, we can use them to solve using whatever method you want.

a = 11 + b

3a = 4b + 4

I will be using matrices RREF to solve for this.

a - b = 11

3a - 4b = 4

\begin{bmatrix}1 & -1  & 11\\3 & -4 & 4 \end{bmatrix}

\begin{bmatrix}1 & 0  & 40\\0 & 1 & 29 \end{bmatrix}

a = 40

b = 29

6 0
3 years ago
The southernmost rim inlet elevation on the topographical survey is
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What is topographical survey?

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6 0
1 year ago
How much metal can be removed from a cracked drum to restore surface
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Explanation:

sc

7 0
2 years ago
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. Using the Newton Raphson method, determine the uniform flow depth in a trapezoidal channel with a bottom width of 3.0 m and si
Over [174]

Answer:

y  ≈ 2.5

Explanation:

Given data:

bottom width is 3 m

side slope is 1:2

discharge is 10 m^3/s

slope is 0.004

manning roughness coefficient is 0.015

manning equation is written as

v =1/n R^{2/3} s^{1/2}

where R is hydraulic radius

S = bed slope

Q = Av =A 1/n R^{2/3} s^{1/2}

A = 1/2 \times (B+B+4y) \times y =(B+2y) y

R =\frac{A}{P}

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R =\frac{(3+2y) y}{(3+2\sqrt{5} y)}

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solving for y100 =(2+2y) y) \times (1/0.015) [\frac{(3+2y) y}{(3+2\sqrt{5} y)}]^{2/3} \times 0.004^{1/2}

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BlackZzzverrR [31]

Answer:

the answer is c

Explanation:

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