<em>Nuclear power releases less radiation into the environment than any other major energy source.</em>
The pH a 0.25 m solution of C₆H₅NH₂ is equal to 3.13.
<h3>How do we calculate pH of weak base?</h3>
pH of the weak base will be calculate by using the Henderson Hasselbalch equation as:
pH = pKb + log([HB⁺]/[B])
pKb = -log(1.8×10⁻⁶) = 5.7
Chemical reaction for C₆H₅NH₂ is:
C₆H₅NH₂ + H₂O → C₆H₅NH₃⁺ + OH⁻
Initial: 0.25 0 0
Change: -x x x
Equilibrium: 0.25-x x x
Base dissociation constant will be calculated as:
Kb = [C₆H₅NH₃⁺][OH⁻] / [C₆H₅NH₂]
Kb = x² / 0.25 - x
x is very small as compared to 0.25, so we neglect x from that term and by putting value of Kb, then the equation becomes:
1.8×10⁻⁶ = x² / 0.25
x² = (1.8×10⁻⁶)(0.25)
x = 0.67×10⁻³ M = [C₆H₅NH₃⁺]
On putting all these values on the above equation of pH, we get
pH = 5.7 + log(0.67×10⁻³/0.25)
pH = 3.13
Hence pH of the solution is 3.13.
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The ph after 17.0 ml of 0.15 m Koh has been added to 15 ml of 0.20 m hclo4 is <u>3.347</u>.
Titration is a commonplace laboratory technique of quantitative chemical analysis to determine the attention of an identified analyte. A reagent, termed the titrant or titrator, is ready as a trendy answer of recognized awareness and extent.
<u>Calculation:-</u>
Normality of acid Normality of base
= nMV nMV
= 1 × 0. 15 × 0.017 1 × 0. 20 ×0.015 L
= 2.55 × 10⁻³ = 3 × 10⁻³
The overall base will be high
net concentration = 3× 10⁻³ - 2.55 × 10⁻³
= 0.45 × 10⁻³
= 4.5× 10⁻⁴
pH = -log[4.5 × 10⁻⁴]
= 4 - log4.4
= <u>3.347</u>
A titration is defined as 'the manner of determining the amount of a substance A by using adding measured increments of substance B, the titrant, with which it reacts till precise chemical equivalence is completed the equivalence factor.
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Answer: The frequency of this light is ![6.62\times 10^{14}s^{-1}](https://tex.z-dn.net/?f=6.62%5Ctimes%2010%5E%7B14%7Ds%5E%7B-1%7D)
Explanation:
To calculate the wavelength of light, we use the equation:
![\lambda=\frac{c}{\nu}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7Bc%7D%7B%5Cnu%7D)
where,
= wavelength of the light =![453nm=453\times 10^{-9}m](https://tex.z-dn.net/?f=453nm%3D453%5Ctimes%2010%5E%7B-9%7Dm)
c = speed of light = ![3.0\times 10^8m/s](https://tex.z-dn.net/?f=3.0%5Ctimes%2010%5E8m%2Fs)
= frequency of light = ?
![\nu=\frac{3.0\times 10^8m/s}{453\times 10^{-9}m}=6.62\times 10^{14}s^{-1}](https://tex.z-dn.net/?f=%5Cnu%3D%5Cfrac%7B3.0%5Ctimes%2010%5E8m%2Fs%7D%7B453%5Ctimes%2010%5E%7B-9%7Dm%7D%3D6.62%5Ctimes%2010%5E%7B14%7Ds%5E%7B-1%7D)
The frequency of this light is ![6.62\times 10^{14}s^{-1}](https://tex.z-dn.net/?f=6.62%5Ctimes%2010%5E%7B14%7Ds%5E%7B-1%7D)