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nata0808 [166]
3 years ago
11

An African Swallow, flying with a horizontal velocity of 80 m/s due North, drops a coconut from a height of 8 m. When does the c

oconut hit the ground after it is released?
Physics
1 answer:
Vesnalui [34]3 years ago
6 0

Answer:

The coconut hit the ground after 1.28 s

Explanation:

Velocity: This can be defined as the rate of change of displacement. Or it is defined as speed in a specified direction. Velocity is a vector quantity. The S.I unit of velocity is m/s.

Using the equation of motion,

S = ut + 1/2gt²....................................... Equation 1

Where S = distance, u = initial velocity, t = time, g = acceleration due to gravity

<em>Given: s= 8 m, u = 0 m/s ( because it was drop from a height), </em>

<em>Constant :   g = +9.8 m/s²</em>

<em>Substituting these values into equation 1,</em>

<em>8 = 0×t + 1/2(9.8×t²)</em>

<em>8 = 4.9t²</em>

<em>t² = 8/4.9</em>

<em>t = √1.63</em>

<em>t = 1.276 s</em>

t = 1.28 s

Therefore the coconut hit the ground after 1.28 s

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