Describe what happens to pressure as the force exerted on a given area increases.

(a) Circular metal wires in electrical circuits may have different cross-sectional areas (different diameters) and different len

WARRIOR [948]

For the different wires the values given are

For Wire A, Area= $A_{A}$ , Resistivity= $ρ_{A}$ , Length= $L_{A}$ , Heat= $H_{A}$ , Voltage= V, Time= t, Wire B, Area= $A_{B}$ , Resistivity= $ρ_{B}$ , Length= $L_{B}$ , Heat= $H_{B}$

So, $H_{A}$ / $H_{A}$ = $\frac{V^{2} *t}{\frac{ρ(1)*L_{A} }{A_{A} } }$ / $\frac{V^{2} *t}{\frac{ρ(2)*L_{B} }{A_{B} } }$

Therefore $H_{A}$ / $H_{A}$ = $\frac{A_{A}*ρ_{B} *L_{B}}{A_{B}ρ_{A} L_{A} }$

The type of energy that moves between two materials with varying temperatures is referred to by scientists as heat. Because the average translational kinetic energy per molecule in the two materials varies, an energy transfer takes place. Up until thermal equilibrium is attained, heat is transferred from the substance with the higher temperature to the material with the lower temperature. The joule, with 1 joule equalling 1 newton meter, is the SI unit of heat. Imagine the following situation to better comprehend what happens when this energy transfer takes place: Tiny rubber balls are bouncing all over two distinct containers that are full with them. The difference between the average ball speed in one container and the second container is substantial.

(a) Circular metal wires in electrical circuits may have different cross-sectional areas (different diameters) and different lengths. For a given applied voltage, how would the joule heat vary with these parameters

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6 0

2 years ago

Viewers of Star Trek hear of an antimatter drive on the Starship Enterprise. One possibility for such a futuristic energy source

Alex_Xolod [135]

Answer:

The magnetic field strength required to hold anti-protons, moving at 5.70 ✕ 10⁷ m/s in a circular path of 3.20 m in radius is 0.186 T.

Explanation:

To solve the question we note that the magnetic force on a moving charge is given by

F = q·v·B

Where

q = Charge

v = Velocity of the charge =5.70 ✕ 10⁷ m/s

B = Magnetic field

Based on Newton's second law,

Force = Mass, m × Acceleration, a = m × a

Where:

a = Acceleration

m = Mass of anti-proton = Mass of proton = 1.6726219 × 10⁻²⁷ kg

We note that for circular motion, acceleration a is given by

$\alpha = \frac{v^{2} }{r}$ .

Where:

r = Radius = 3.20 m

Therefore, for the circular motion, force, F = $\frac{m\cdot v^{2} }{r}$

Equating the magnetic force equation to the circular force equation, we have

$\frac{m\cdot v^{2} }{r}$ = q·v·B So that, we find B by making the subject of the formula as follows

$B= \frac{m\times v^{2} }{r\times q \times v}$ . Which gives

$B= \frac{m\times v }{r\times q} = \frac{(1.6726219 \times 10^{-27}) \times (5.7\times 10^{7}) }{(3.20)\times (1.602\times 10^{-19}) }$ = 0.186 T

The magnetic field strength is

B = 0.186 T

4 0

3 years ago

So my grades have come up a little but also went down a lot This app has really helped me!!

ddd [48]

Answer:

yay im proud keep going on bro

6 0

3 years ago

Read 2 more answers

Solve for (b) how many revolutions it takes for the cd to reach its maximum angular velocity in 1.36s?

Digiron [165]

Angular displacement of the cd is 3.25 rev

Explanation:

The question is incomplete. It is not given what is the maximum angular velocity of the cd.

Here we are going to assume that the maximum angular velocity is:

$\omega = 30 rad/s$

The motion of the cd is an accelerated angular motion, therefore we can use the following suvat equation:

$\theta = (\frac{\omega_0 + \omega}{2})t$

where:

$\theta$ is the angular displacement of the cd during the time interval t

$\omega_0$ is the initial angular velocity of the cd

$\omega$ is the final angular velocity

Here we have:

t = 1.36 s

$\omega_0 = 0$ (assuming the cd starts from rest)

Therefore, the angular displacement of the cd during this time is:

$\theta=(\frac{0+30}{2})(1.36)=20.4 rad$

And since $1 rev = 2 \pi rad$ , we can convert into number of revolutions completed:

$\theta = 20.4 rad \cdot \frac{1}{2\pi rad/rev}=3.25 rev$

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8 0

3 years ago

21. Which oi the following is something that all living organisms have in common

irga5000 [103]

They need resources such as food and sometimes water

6 0

4 years ago