Question

A merry go round (mass of 200kg and radius 5m) is rotating so that the outside edge is moving 10m/s. A giant bug of 6kd at a distance of 4m from the center. What is the angular velocity of the merry go round?

Answer 1

Answer:

2 rad/s

Explanation:

For a rotating object, the linear velocity is given by

$v=\omega r$

where $\omega$ is the angular velocity and $r$ is the radius.

$\omega=\dfrac{v}{r}$

The edge has a linear velocity of 10 m/s and the radius at the edge is 5 m.

$\omega=\dfrac{10 \text{ m/s}}{5 \text{ m}} = 2 \text{ rad/s}$