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ruslelena [56]
3 years ago
7

A merry go round (mass of 200kg and radius 5m) is rotating so that the outside edge is moving 10m/s. A giant bug of 6kd at a dis

tance of 4m from the center. What is the angular velocity of the merry go round?
Physics
1 answer:
romanna [79]3 years ago
8 0

Answer:

2 rad/s

Explanation:

For a rotating object, the linear velocity is given by

v=\omega r

where \omega is the angular velocity and r is the radius.

\omega=\dfrac{v}{r}

The edge has a linear velocity of 10 m/s and the radius at the edge is 5 m.

\omega=\dfrac{10 \text{ m/s}}{5 \text{ m}} = 2 \text{ rad/s}

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