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IRINA_888 [86]
3 years ago
12

A friend would like you to build an "electronic eye" for use as a fake security device. The device consists of three lights line

d up in a row, controlled up by the outputs left, Middle, and Right, which if asserted, indicate that a light should be on. Only one light is on at a time, and the light moves from left to right. Only one light is on at a time, and the light moves from left to right and then from right to left, thus scaring away thieves who believe that the device is monitoring their activity.
Draw the graphical representation for the finite state machine used to specify the electronic eye. Note that the rate of the eyes movement will be controlled by the clock speed (which should not be too great) and there are essentially no inputs.

Engineering
2 answers:
mars1129 [50]3 years ago
8 0

Answer and explanation:

The graphical representation of the electronic eye

The state table showing

the present state

input

Next state and

the output

are shown in the attached file

lapo4ka [179]3 years ago
3 0

Answer:

  see attached

Explanation:

The state table and graphical state diagram are shown. Transitions between states occur on each clock. The marking in each state is the state name and the (L, M, R) output condition.

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A driver is traveling at 90 km/h down a 3% grade on good, wet pavement. An accident
Paul [167]

Answer:

0.35

Explanation:

We resolve the component of the weight of the car along and perpendicular to the grade. We have mgsinФ and mgcosФ where Ф = angle of grade.

Now, the frictional force f = μN = μmgcosФ where μ = coefficient of friction

So, the net force along the grade is F = mgsinФ - μmgcosФ.

The work done by this force moving a distance, d along the grade is

W = (mgsinФ - μmgcosФ)d

This work equals the change in kinetic energy of the car. So ΔK = 1/2m(v₂² - v₁²) = W = (mgsinФ - μmgcosФ)d

1/2m(v₂² - v₁²) = (mgsinФ - μmgcosФ)d

1/2(v₂² - v₁²) = (gsinФ - μgcosФ)d

(v₂² - v₁²)/2d = (gsinФ - μgcosФ)

dividing through by gcosФ, we have

(v₂² - v₁²)/2dgcosФ = (gsinФ/gcosФ) - μgcosФ/gcosФ

(v₂² - v₁²)/2dgcosФ = tanФ -  μ

μ = tanФ - (v₂² - v₁²)/2dgcosФ

given that tanФ = 3% = 3/100 and 1 + tan²Ф = 1/cos²Ф, cosФ = 1/(√1 + tan²Ф) = 1/(√1 + (3/100)²) = 1/(√1 + (9/10000)) = 1/(√10000 + 9/10000) = 1/√(10009/10000) = 100/√10009 = 100/100.05 = 0.9995.

Also, given that v₁ = 90 km/h = 90 × 1000/3600 m/s = 25 m/s and v₂ = 45 km/h = 45 × 1000/3600 m/s = 12.5 m/s, d = 75 m and g = 9.8 m/s².

So, substituting the values of the variables into the equation, we have

μ = tanФ - (v₂² - v₁²)/2dgcosФ

μ = 3/100 - ((12.5 m/s)² - (25 m/s)²)/(2 × 75 m × 9.8 m/s² × 0.9995)

μ = 3/100 - ((156.25 m/s)² - (625 m/s)²)/1,469.265 m²/s²

μ = 3/100 - (-468.75 m²/s²)/1,469.265 m²/s²

μ = 3/100 + 468.75 m²/s²/1,469.265 m²/s²

μ = 0.03 + 0.32

μ = 0.35

So, theoretical friction  coefficient is 0.35

4 0
3 years ago
How would I find the Voltage across the open circuit
Nimfa-mama [501]

Answer:

  Vab = 80V

Explanation:

The only current flowing in the circuit is supplied by the 100 V source. Its only load is the 40+60 ohm series circuit attached, so the current in that loop is (100V)/(40+60Ω) = 1A. That means V1 = (1A)(60Ω) = 60V.

Vab will be the sum of voltages around the right-side "loop" between terminals 'a' and 'b'. It is (working clockwise from terminal 'b') ...

  Vab = -10V +60V +(0A×10Ω) +30V

  Vab = 80V

3 0
2 years ago
Consider that a system has two entities, Students, Instructors and Course. The Student has the following properties: student nam
tekilochka [14]

Answer:

There's no answer ?

Explanation:

5 0
3 years ago
When were dresses made
klio [65]

Answer:

The world's oldest dress called the Tarkhan Dress is at 5,100 to 5,500 years of age.

Does that help? Or do you need something else? I can change my answer if this is not what you need! :D

Explanation:

6 0
3 years ago
List all possible fracture mechanisms under which the unidirectional composites fail. Briefly explain and describe the related m
professor190 [17]

Answer:

Ususushehehehhuuiiïbbb

Explanation:

Yyshehshehshshsheyysysueueue

7 0
2 years ago
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