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IRINA_888 [86]
3 years ago
12

A friend would like you to build an "electronic eye" for use as a fake security device. The device consists of three lights line

d up in a row, controlled up by the outputs left, Middle, and Right, which if asserted, indicate that a light should be on. Only one light is on at a time, and the light moves from left to right. Only one light is on at a time, and the light moves from left to right and then from right to left, thus scaring away thieves who believe that the device is monitoring their activity.
Draw the graphical representation for the finite state machine used to specify the electronic eye. Note that the rate of the eyes movement will be controlled by the clock speed (which should not be too great) and there are essentially no inputs.

Engineering
2 answers:
mars1129 [50]3 years ago
8 0

Answer and explanation:

The graphical representation of the electronic eye

The state table showing

the present state

input

Next state and

the output

are shown in the attached file

lapo4ka [179]3 years ago
3 0

Answer:

  see attached

Explanation:

The state table and graphical state diagram are shown. Transitions between states occur on each clock. The marking in each state is the state name and the (L, M, R) output condition.

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Plant scientists would not do which of the following?
zavuch27 [327]

Explanation:

i think option 4 is correct answer because itsrelated to animal not plants.

6 0
3 years ago
Read 2 more answers
Water flows with an average speed of 6.5 ft/s in a rectangular channel having a width of 5 ft The depth of the water is 2 ft.
lisov135 [29]

Answer:

specific energy  = 2.65 ft

y2 = 1.48 ft  

Explanation:

given data

average speed v = 6.5 ft/s

width = 5 ft

depth of the water y = 2 ft

solution

we get here specific energy that is express as

specific energy = y + \frac{v^2}{2g}     ...............1

put here value and we get

specific energy = 2 + \frac{6.5^2}{2\times 9.8\times 3.281}  

specific energy  = 2.65 ft

and

alternate depth is

y2 = \frac{y1}{2} \times (-1+\sqrt{1+8Fr^2})  

and

here Fr² = \frac{v1}{\sqrt{gy}}  = \frac{6.5}{\sqrt{32.8\times 2}}  

Fr² = 0.8025

put here value and we get

y2 = \frac{2}{2} \times (-1+\sqrt{1+8\times 0.8025^2})

y2 = 1.48 ft  

7 0
3 years ago
Jjjjjmmmmmmmmmml.n;nLN/n/kn
GaryK [48]
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6 0
3 years ago
What is -4 (negative 4) in a 2's complement of 8 bits?
Pachacha [2.7K]

Answer: Yes

Explanation: -4 x 2 = 8

5 0
3 years ago
A four-cylinder, four-stroke internal combustion engine operates at 2800 RPM. The processes within each cylinder are modeled as
marysya [2.9K]

Answer:

1) 287760.4 Hp

2) 18410899.5 kPa

Explanation:

The parameters given are;

p₁ = 14.7 lbf/in² = 101325.9 Pa

v₁ = 0.0196 ft³ = 0.00055501 m³

T₁ = 80°F = 299.8167 K

k = 1.4

Assumptions;

1) Air standard conditions are appropriate

2) There are negligible potential and kinetic energy changes

3) The air behaves as an ideal gas and has constant specific heat capacities of temperature and pressure

1) Process 1 to 2

Isentropic compression

T₂/T₁ = (v₁/v₂)^(1.4 - 1) = 10^0.4

p₂/p₁ = (v₁/v₂)^(1.4)

p₂ = p₁×10^0.4 =  101325.9*10^0.4 = 254519.153 Pa

T₂ = 299.8167*10^0.4 = 753.106 K

p₃ = 1080 lbf/in² = 7,446,338 Pa

Stage 2 to 3 is a constant volume process

p₃/T₃ = p₂/T₂

7,446,338/T₃ =   254519.153/753.106

T₃ = 7,446,338/(254519.153/753.106) = 22033.24 K

T₃/T₄ = (v₁/v₂)^(1.4 - 1) = 10^0.4

T₄ = 22033.24/(10^0.4) = 8771.59 K

The heat supplied, Q₁ = cv(T₃ - T₂) = 0.718*(22033.24 -753.106) = 15279.14 kJ

The heat rejected = cv(T₄ - T₁) = 0.718*(8771.59 - 299.8167) = 6082.73 kJ

W(net) = The heat supplied - The heat rejected = (15279.14 - 6082.73) = 9196.41 kJ

The power = W(net) × RPM/2*1/60 = 9196.41 * 2800/2*1/60 = 214582.9 kW

The power by the engine = 214582.9 kW = 287760.4 Hp

2) The mean effective pressure, MEP  = W(net)/(v₁ - v₂)

v₁ = 0.00055501 m³

v₁/v₂ = 10

v₂ = v₁/10 = 0.00055501/10 = 0.000055501

MEP  = 9196.41/(0.00055501 -  0.000055501) = 18410899.5 kPa

4 0
2 years ago
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