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3 years ago

What is the kinetic energy that the device contains immediately before it hits the ground? [KE = /2mv-]

Physics

1 answer:

n200080 [17]3 years ago

6 0

Answer:

Kinetic energy : "It is the energy possessed by body by virtue of its motion" .

Explanation:

The mechanical energy is the energy that a body has due to its motion or position .

It is of two types :

Potential energy
Kinetic energy

Potential energy

"It is the energy that a body has due to its position or state" .

It is given by P.E=mgh

Kinetic energy

"It is the energy that a body has due to its motion" .

The formula is : K.E=1/2mv².

For example

A ball is placed on table .
At that time it has potential energy .
Now,lets say that we push it and it drops down .
On doing this ,the potential energy of ball gets converted into kinetic energy(because it comes in motion ) and as soon as it touches the ground it stops and its kinetic energy gets converted into Potential energy again .

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A pilot is upside down at the top of an inverted loop of radius 3.20 x 103 m. At the top of the loop his normal force is only on

n200080 [17]

Answer:

6858.5712 m/s

Explanation:

Given that:

Radius, r

R = 3.20 * 10^3.

Normal force = 0.5 * normal weight

Normal force = Fn ; Normal weight = Fg

Fn = 0.5Fg

Recall:

mv² / R = Fn + Fg

Fn = 0.5Fg

mv² / R = 0.5Fg + Fg

mv² /R = 1.5Fg

mv² = 1.5Fg * R

F = mg

mv² = 1.5* mg * R

v² = 1.5gR

v = sqrt(1.5gR)

V = sqrt(1.5 * 9.8 * 3.2 * 10^3)

V = sqrt(47.04^3)

V = 6858.5712 m/s

6 0

2 years ago

Consider a metal single crystal oriented such that the normal to the slip plane and the slip direction are at angles of 60 and 3

Scilla [17]

Explanation:

Given that,

Angle by the normal to the slip α= 60°

Angle by the slip direction with the tensile axis β= 35°

Shear stress = 6.2 MPa

Applied stress = 12 MPa

We need to calculate the shear stress applied at the slip plane

Using formula of shear stress

$\tau=\sigma\cos\alpha\cos\beta$

Put the value into the formula

$\tau=12\cos60\times\cos35$

$\tau=4.91\ MPa$

Since, the shear stress applied at the slip plane is less than the critical resolved shear stress

So, The crystal will not yield.

Now, We need to calculate the applied stress necessary for the crystal to yield

Using formula of stress

$\sigma=\dfrac{\tau_{c}}{\cos\alpha\cos\beta}$

Put the value into the formula

$\sigma=\dfrac{6.2}{\cos60\cos35}$

$\sigma=15.13\ MPa$

Hence, This is the required solution.

3 0

3 years ago

A force of 3 newtons moves a 10 kilogram mass horizontally a distance of 3 meters. The mass does not slow down or speed up as it

Mashutka [201]

Answer:

9 joules of heat energy was produced

Explanation: there is no acceleration therefore its not a kinetic energy

Energy= force × distance

= 3×3

3 0

3 years ago

What formula is used to find an objects acceleration

ololo11 [35]

Acceleration = velocity / time.

7 0

3 years ago

A ball is thrown upward with an initial velocity of 13 m/s. Using the approximate value of

dem82 [27]

Answer:

v=v0 - gt

Explanation:

The equation for velocity is

v=v0 - gt

where v0=14m/s, g=10m/s^2.

in 1 second:

v=14-10=4m/s

it is positive so direction is upwards

in 2 seconds:

v=14-20=-6m/s

it is negative so direction is downwards

5 0

2 years ago

What is the kinetic energy that the device contains immediately before it hits the ground? [KE = /2*m*v-]

What is the kinetic energy that the device contains immediately before it hits the ground? [KE = /2mv-]