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3 years ago

What is the kinetic energy that the device contains immediately before it hits the ground? [KE = /2mv-]

Physics

1 answer:

n200080 [17]3 years ago

6 0

Answer:

Kinetic energy : "It is the energy possessed by body by virtue of its motion" .

Explanation:

The mechanical energy is the energy that a body has due to its motion or position .

It is of two types :

Potential energy
Kinetic energy

Potential energy

"It is the energy that a body has due to its position or state" .

It is given by P.E=mgh

Kinetic energy

"It is the energy that a body has due to its motion" .

The formula is : K.E=1/2mv².

For example

A ball is placed on table .
At that time it has potential energy .
Now,lets say that we push it and it drops down .
On doing this ,the potential energy of ball gets converted into kinetic energy(because it comes in motion ) and as soon as it touches the ground it stops and its kinetic energy gets converted into Potential energy again .

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You sit at the middle of a large turntable at an amusement park as it is set spinning on nearly frictionless bearings, and then

jolli1 [7]

Answer:

Decrease

Explanation:

If you crawl to the rim the rotational speed will decrease. The law of conservation of angular momentum supports this answer. And it states that :

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3 years ago

You want to manufacture a guitar such that the instrument will be in tune when each of the strings are tightened to the same ten

charle [14.2K]

Answer:

0.000507 kg/m

Explanation:

L = Length of string

T = Tension

$\mu$ = Mass density of string

E denotes the E string

D denotes the D String

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$f=\dfrac{1}{2L}\sqrt{\dfrac{T}{\mu}}$

$f\propto \sqrt{\dfrac{1}{\mu}}$

$\dfrac{f_D}{f_E}=\sqrt{\dfrac{\mu_E}{\mu_D}}\\\Rightarrow \mu_E=\dfrac{f_D^2}{f_E^2}\mu_D\\\Rightarrow \mu_E=\dfrac{146.83^2}{329.63^2}\times 0.00256\\\Rightarrow \mu_E=0.000507\ kg/m$

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8 0

3 years ago

While playing catch with my dog I bounced the ball off the ground at a 30-degree angle. It had a range of 6 meters.

baherus [9]

The initial velocity of the ball is 8.2 m/s

Explanation:

The motion of the ball is a projectile motion, which consists of two separate motions:

- A uniform motion along the horizontal direction, at constant velocity

- A uniformly accelerated motion along the vertical direction, with constant acceleration ( $g=9.8 m/s^2$ , acceleration of gravity)

The range of a projectile can be derived by the equation of motions along the two directions, and it is found to be:

$d=\frac{v^2 sin 2\theta}{g}$

where

v is the initial velocity of the projectile

$\theta$ is the angle of projection

g is the acceleration of gravity

For the ball in this problem, we have

$\theta=30^{\circ}$

d = 6 m is the range

Solving for v, we find the initial velocity:

$v=\sqrt{\frac{gd}{sin 2\theta}}=\sqrt{\frac{(9.8)(6)}{sin (2\cdot 30^{\circ})}}=8.2 m/s$

Learn more about projectile motion:

brainly.com/question/8751410

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3 years ago

Outside the space shuttle, you and a friend pull on two ropes to dock a satellite whose mass is 700 kg. The satellite is initial

MaRussiya [10]

Answer:

your friend did a work of 1717.34 J

Explanation:

The sum of the work made by your friend and you is equal the change in the kinetic energy, so:

$W_a+W_b=\frac{1}{2}mv_f^{2}-\frac{1}{2}mv_i^{2}$

Where $W_a$ is the work that you did, $W_b$ is the work that your friend did, m is the mass of the satellite and $v_f$ and $v_i$ are the final and initial speeds