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liubo4ka [24]
4 years ago
10

Use the Periodic Table of the Elements to answer

Chemistry
1 answer:
Juliette [100K]4 years ago
6 0

Answer:

b. lithium

Explanation:

Li the least likely, to lose an electron.

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Which state of matter has a definite volume and takes the shape of its container?
maksim [4K]

Answer:

Explanation:

liquid only is the matter which has a definite volume and takes the shape of its container

5 0
4 years ago
Read 2 more answers
write down the balanced chemical equation of the reaction that takes place between iron and concentrated sulphuric acid​
pishuonlain [190]

Answer:

2Fe + 3H2SO4 → Fe2(SO4)3 + 3H2

Explanation:

Iron is a metallic element with chemical symbol, Fe while concentrated sulphuric acid is a chemical compound with chemical formula, H2SO4. Both are involved in a chemical reaction as follows:

Fe + H2SO4 → Fe2(SO4)3 + H2

However, this reaction is not balanced as the number of moles of each atom in both the reactants and product side is not equal. To balance the equation, we have to ensure that each number of atom is equal. The balanced equation are as follows:

2Fe + 3H2SO4 → Fe2(SO4)3 + 3H2

5 0
3 years ago
Qual substância apresenta 2 (dois) pares de elétrons sendo compartilhados entre seus átomos na
-Dominant- [34]

Answer:

Explanation:

a bucusev 35ft

3 0
3 years ago
Calculate the amount of heat released in the combustion of 10.5 grams of Al with 3 grams of O2 to form Al2O3(s) at 25°C and 1 at
ElenaW [278]

Answer : The amount of heat released in the combustion is, 209.5 kJ

Explanation :

First we have to calculate the moles of Al and O_2.

\text{ Moles of }Al=\frac{\text{ Mass of }Al}{\text{ Molar mass of }Al}=\frac{10.5g}{27g/mole}=0.389moles

\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{3g}{32g/mole}=0.188moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction will be:

4Al+3O_2\rightarrow 2Al_2O_3

From the balanced reaction we conclude that

As, 3 mole of O_2 react with 4 mole of Al

So, 0.188 moles of O_2 react with \frac{4}{3}\times 0.188=0.251 moles of Al

From this we conclude that, Al is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of Al_2O_3

From the reaction, we conclude that

As, 3 mole of O_2 react to give 2 mole of Al_2O_3

So, 0.188 moles of O_2 react to give \frac{2}{3}\times 0.188=0.125 moles of Al_2O_3

Now we have to calculate the amount of heat released in the combustion.

As, 1 mole of Al_2O_3 releases amount of heat = 1676 kJ

So, 0.125 mole of Al_2O_3 releases amount of heat = 0.125\times 1676kJ=209.5kJ

Thus, the amount of heat released in the combustion is, 209.5 kJ

4 0
3 years ago
How to balance _h2s+ _o2 = _h2o+ _s
goldfiish [28.3K]

Answer:

<u>2</u>H₂S + <u>1</u>O₂ → <u>2</u>H₂O + <u>2</u>S

Explanation:

<u>SOLUTION :-</u>

Balance it by using 'hit & trial' method , and you'll get the answer :-

<u>2</u>H₂S + <u>1</u>O₂ → <u>2</u>H₂O + <u>2</u>S

<u></u>

<u>VERIFICATION :-</u>

<em>In reactant side of equation :-</em>

  • Number of atoms in H = 2×2 = 4
  • Number of atoms in S = 2×1 = 2
  • Number of atoms in O = 1×2 = 2

<em>In product side of equation :-</em>

  • Number of atoms in H = 2×2 = 4
  • Number of atoms in O = 2×1 = 2
  • Number of atoms in S = 2×1 = 2

Number of atoms of each element is equal in both reactant & product side of equation. Hence , the equation is balanced.

5 0
3 years ago
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