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Yuki888 [10]
3 years ago
13

How many mold are in 4.25x10^-2 atoms of lead

Chemistry
1 answer:
Shalnov [3]3 years ago
7 0
I’m sorry I have no clue
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Answer:

\Large \boxed{\mathrm{Group \ 4}}

Explanation:

The number of valence electrons tells us the group number of the neutral atom.

The atom has 4 valence electrons.

The atom is in group 4.

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Which best compares 1 mol of sodium chloride to 1 mol of aluminum chloride?
lesya692 [45]
<span>Mol is the unit of amount of substance. It is equal to 6.02 x 10^23 molecules. Now, One mol of Sodium chloride (NaCl) contains 6.022x 10^23 molecules of NaCl. Also, the number atoms of both Na (sodium) and Cl (chlorine) will be equal. Similatly, One mol of Aluminium Chloride (AlCl3) contains 6.022x 10^23 molecules of (AlCl3) but the ratio of Al and Cl atoms will be 1:3</span>
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3 years ago
List the procedural steps, from start to finish, that are required to convert 2‑naphthol and allyl bromide into allyl 2‑naphthyl
elena-14-01-66 [18.8K]
<h3>Procedural steps are: - </h3>
  1. On a small scale, the reaction is carried out by combining the alcohol, the haloalkane, and the phase transfer catalyst in a conical vial.
  2. To start the reaction, sodium hydoxide (base) is added.
  3. To prevent solvent evaporation, the reaction flask is covered and stirred during the reaction.
  4. TLC monitors the reaction's progress to ensure that no time is wasted.
  5. To remove any remaining water, the reaction solution is dried over calcium chloride.
  6. Column chromatography is used to purify the product, and evaporation is used to collect it.
<h3>What is Catalysis?</h3>

Catalysis is the process of boosting the pace of a chemical reaction by using a catalyst. Catalysts are not consumed in the reaction and so survive it.

To learn more about catalysis from the given link

brainly.com/question/1372992

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8 0
1 year ago
What is the pH of a buffer that consists of 0.254 M CH3CH2COONa and 0.329 M CH3CH2COOH? Ka of propanoic acid, CH3CH2COOH is 1.3
Shtirlitz [24]

Answer:

4.77 is the pH of the given buffer .

Explanation:

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[salt]}{[acid]})

pH=-\log[K_a]+\log(\frac{[salt]}{[acid]})

pH=-\log[K_a]+\log(\frac{[CH_3CH_2COONa]}{[CH_3CH_2COOH]})

We are given:

K_a = Dissociation constant of propanoic acid = 1.3\times 10^{-5}

[CH_3CH_2COONa]=0.254 M

[CH_3CH_2COOH]=0.329 M

pH = ?

Putting values in above equation, we get:

pH=-\log[1.3\times 10^{-5}]+\log(\frac{[0.254 M]}{[0.329]})

pH = 4.77

4.77 is the pH of the given buffer .

7 0
3 years ago
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