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Yuki888 [10]
3 years ago
13

How many mold are in 4.25x10^-2 atoms of lead

Chemistry
1 answer:
Shalnov [3]3 years ago
7 0
I’m sorry I have no clue
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The specific heat of aluminum is 0.897j/(g•°C). If a 22.6 g sample of aluminum is heated from 25°C to 250°C, then how much heat
Oxana [17]

Q=mcat

=(22.6)(.897)(250-25)

4,561.245 or 4.5 * 10^-3

3 0
3 years ago
HELP PLEASE Brainliest
igomit [66]

Answer: B) The trees where peppered moths rest become lighter in color.

3 0
4 years ago
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How many moles are in a sample of 4.55 x 10^24 molecules of C3H8?​
mestny [16]

Answer: 7.56 moles

Explanation:

C3H8 is the chemical formula for propane, the third member of the alkane family.

Recall that based on Avogadro's number, 1 mole of any substance has 6.02 x 10^23 atoms

So 1 mole of C3H8 = 6.02 x 10^23 atoms

Z moles of C3H8 = 4.55 x 10^24 atoms

To get the value of Z, we cross multiply:

1 x 4.55 x 10^24 atoms = Z moles x (6.02 x 10^23 atoms)

4.55 x 10^24 atoms = Z moles x (6.02 x 10^23 atoms)

To get the value of Z divide both sides by 6.02 x 10^23 atoms

Z moles =4.55 x 10^24 atoms ➗ 6.02 x 10*23 atoms

Hence, Z = 7.56 moles

Thus, the number of propane, C3H8 is 7.56 moles

7 0
3 years ago
Which of the following physicists paved the path for experiments with subatomic particles with his discovery of the
Setler [38]

Answer: OJJ Thompson

Explanation:

6 0
4 years ago
method to measure soluble organic carbon in seawater includes oxidation of the organic materials to CO2 with K2S2O8, followed by
dusya [7]

Answer:

The ppm carbon in the seawater is 104.01.

Explanation:

Mass of seawater = 6.234 g

Mass of carbon dioxide gas  produced = 2.378 mg = 0.002378 g

1 mg = 0.001 g

Moles of carbon dioxide gas = \frac{0.002378 g}{44.009 g/mol}=5.4034\times 10^{-5} mol

1 mol of carbon dioxde gas has 1 mole pf carbon atoms,then 5.4034\times 10^{-5} mol will have ;

1\times 5.4034\times 10^{-5} mol=5.4034\times 10^{-5} mol of carbon

Mass of 5.4034\times 10^{-5} mol of carbon ;

12 g/mol\times 5.4034\times 10^{-5} mol=0.0006484 g

To calculate the ppm of oxygen in sea water, we use the equation:

\text{ppm}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^6

(Both the masses are in grams)

=\frac{0.0006484 g}{ 6.234 g}\times 10^6=104.01 ppm

The ppm carbon in the seawater is 104.01.

7 0
4 years ago
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