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TiliK225 [7]
4 years ago
11

Roshan makes the table below to describe how to draw a ray diagram for a convex lens.

Physics
2 answers:
slamgirl [31]4 years ago
5 0

Answer:

B

Explanation:

Took the test

Mariana [72]4 years ago
4 0

May you please provide a picture of the table, so that I can see his error?  Otherwise I can not solve.

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A comet of mass 1.20 × 10¹⁰kg moves in an elliptical orbit around the Sun. Its distance from the Sun ranges between 0.500 AU and
irina [24]

The eccentricity of its orbit is $$U=-2.13 \times 10^{17} \mathrm{~J} .\end{aligned}$$

<h3>What is mass?</h3>
  • Mass is a physical body's total amount of matter. It also serves as a gauge for the body's inertia or resistance to acceleration (change in velocity) in the presence of a net force. The strength of an object's gravitational pull to other bodies is also influenced by its mass.
  • The kilogram is the SI unit of mass (kg). In science and technology, a body's weight in a given reference frame is the force that causes it to accelerate at a rate equal to the local acceleration of free fall in that frame.
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The length of the semi-major axis is calculated as follows:

where, $G=6.67 \times 10^{-1} \mathrm{~m}^3 / \mathrm{kgs}$

$M=1.99 \times 10^{30} \mathrm{~kg}=$mass of sur

$m=1.20 \times 10^{10} \mathrm{~kg}$ - a mass of the comet

$$\begin{aligned}\therefore \quad \text { At aphelion, } r &=50 \times U \\&=50 \times 1.496 \times 10^{11} \mathrm{~m} . \\U=-\frac{6.67 \times 10^{-11} \times \mathrm{m} 1.99 \times 10^{30} \times 1.20 \times 10^{10}}{50 \times 1.496 \times 10^{11}} \\U=-2.13 \times 10^{17} \mathrm{~J} .\end{aligned}$$

$$U=-2.13 \times 10^{17} \mathrm{~J} .\end{aligned}$$

To learn more about mass, refer to:

brainly.com/question/3187640

#SPJ4

4 0
2 years ago
Temperature and kinetic energy have a_______relationship.
Alex73 [517]
The hotter an object is, the more kinetic energy it has, but i'm not sure what is the exact word missing??
8 0
3 years ago
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A 0.20 kg mass is oscillating at a small angle from a light string with a period of 0.78 s.
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Answer:

L = 15 cm

Explanation:

T = 2π√(L/g)

L = g(T/2π)²

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L = 0.151027... m

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If the wind or current is pushing your boat away from the dock as you prepare to dock, which line should you secure first?
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If the wind or current is pushing your boat away from the dock, bow line should be secured first.

1- We should cast off the bow and stern lines.

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3-Leave the boat on its own for sometime and let the wind or current carry the boat away from the dock.

4 - As you see there is sufficient clearance, shift into forward gear and slowly leave the area.

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