(II) A 20.0-kg box rests on a table. (a) What is the weight of the box and the normal force acting on it? (b) A 10.0-kg box is p
laced on top of the 20.0-kg box, as shown in Fig. 4–43. Determine the normal force that the table exerts on the 20.0-kg box and the normal force that the 20.0-kg box exerts on the 10.0-kg box.
1 answer:
*Fig is Attached with answer*
Answer:
(a) Weight = Normal Force = 196.2 N
(b) Normal force table on 20 kg box = 294.3 N
Normal force 20 kg box on 10 kg box = 98.1 N
Explanation:
(a) Mass = m = 20 kg g = 9.81 m/s²
Weight = w = mg
w = 20 × 9.81
w = 196.2 N
As the box rests on the table so, normal force (NF) must be equal to the weight of the box.
NF = w = 196.2 N
(b)
m₁ = 20 kg m₂ = 10 kg
total mass = M = 30 kg
Total Weight = W = Mg
= 30 × 9.81
= 294.3 N
As both the boxes rest on the table so, normal force (NF) must be equal to the total weight of the boxes.
NF = W = 294.3 N
Weight of 10 kg box = 10 × 9.81 = 98.1 N
As the 10 kg box is placed on the top of 20 kg box, So 20 kg box must exert a normal force that is equal to the weight of 10 kg box.
Normal Force = Weight of 10 kg box = 98.1 N
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Explanation:
Answer:
The second projectile was 1.41 times faster than the first.
Explanation:
In the ballistic pendulum experiment, the speed (v) of the projectile is given by:
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To know how many times faster was the second projectile than the first, we need to take the ratio for the velocities for the projectiles 2 and 1:
(1)
<em>where m₁ and m₂ are the masses of the projectiles 1 and 2, respectively, and h₁ and h₂ are the maximum height reached by the pendulum by the projectiles 1 and 2, respectively. </em>
Since the projectile 1 has the same mass that the projectile 2, we can simplify equation (1):
Therefore, the second projectile was 1.41 times faster than the first.
I hope it helps you!